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kompoz [17]
3 years ago
8

What's equivalent to this polynomial: (10g^3-8g^2+5g-14)+(10g^2+12g)

Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
6 0
<span>10g³+2g²+17g-14

Hope I helped! ( Smiles )</span>
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X×9=y, y-70=11 , y=?​
solmaris [256]

Answer:

y=81

Step-by-step explanation:

x=9 and y=81

y-70=11 (add 70 onto 11)

y=81

5 0
2 years ago
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Plz help me
Snowcat [4.5K]

Answer:

9/4 as a fraction or 2.25 as a decimal

Step-by-step explanation:

6 0
3 years ago
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Triangle DEF has vertices D(−4, 1), E(2, 3), and F(2, 1) and is dilated by a factor of 3 using the point (1, 1) as the point of
CaHeK987 [17]

Answer: D'(-14,1);\ E'(4,7);\ F'(4,1)

Step-by-step explanation:

Since the center of dilation is not at the origin, we can use the following formula in order to find the coordinates of the vertices of the triangle D'E'F':

D_{O,k}(x,y)=(k(x-a)+a, k(y-b)+b)

Where "O" is the center of dilation at (a,b) and "k" is the scale factor.

In this case you can identify that:

(a,b)=(1,1)\\k=3

Therefore, susbtituting values into the formula shown above, you get that the coordinates ot the resulting triangle D'E'F, are the following:

Vertex D' → (3(-4-1)+1,\ 3(1-1)+1)=(-14,1)

Vertex E' → (3(2-1)+1,\ 3(3-1)+1)=(4,7)

Vertex F' → (3(2-1)+1,\ 3(1-1)+1)=(4,1)

6 0
3 years ago
What is the relationship and what is the M
kenny6666 [7]
Answer:

m∠b = 76

Step-by-step explanation:

Opposite sides are congruent and measure the exact same thing

8 0
2 years ago
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QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu
Andru [333]

Answer:

(a)Revenue=580x-10x²,

Marginal Revenue=580-20x

(b)Fixed Cost, =900

Marginal Cost,=300+50x

(c)Profit Function=280x-900-35x²

(d)x=4

Step-by-step explanation:

The price, p = 580 − 10x where x is the number of cakes sold per day.

Total cost function,c = (30+5x)²

(a) Revenue Function

R(x)=x*p(x)=x(580 − 10x)

R(x)=580x-10x²

Marginal Revenue Function

This is the derivative of the revenue function.

If R(x)=580x-10x²,

R'(x)=580-20x

(b)Total cost function,c = (30+5x)²

c=(30+5x)(30+5x)

=900+300x+25x²

Therefore, Fixed Cost, =900

Marginal Cost Function

This is the derivative of the cost function.

If c(x)=900+300x+25x²

Marginal Cost, c'(x)=300+50x

(c)Profit Function

Profit, P(x)=R(x)-C(x)

=(580x-10x²)-(900+300x+25x²)

=580x-10x²-900-300x-25x²

P(x)=280x-900-35x²

(d)To maximize profit, we take the derivative of P(x) in (c) above and solve for its critical point.

Since P(x)=280x-900-35x²

P'(x)=280-70x

Equate the derivative to zero

280-70x=0

280=70x

x=4

The number of cakes that maximizes profit is 4.

5 0
2 years ago
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