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Maksim231197 [3]
3 years ago
10

Please help! Limits. Just confirm that an coverages to 2 as n-->infinity

Mathematics
1 answer:
Alexxandr [17]3 years ago
7 0

Answer:

Limit is 2

Step-by-step explanation:

The last term approaches zero as n approaches infinity so the fuction approaches 2.

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oksian1 [2.3K]

Answer:

1095$ should be invested today .

Step-by-step explanation:

The formula of present value will be applied here :

Present Value= Future Value/(1+ interest rate)^Years

Present Value = 1250/(1.045)^3

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mr Goodwill [35]

Answer:

The coordinates of E are E(x,y) = \left(\frac{9}{2}, 0 \right).

Step-by-step explanation:

The triangle ABC represents a right triangle as both sides AB and AC are orthogonal to each other. The side AB is in the y axis, whereas the side AC is in the x axis. The triangle is dilated with respect to the origin, in which point A is set.

Vectorially speaking, dilation is defined by the following operation:

P'(x,y) = O(x,y) + k\cdot [P(x,y) - O(x,y)] (1)

Where:

O(x,y) - Point of reference.

P(x,y) - Original point.

P'(x,y) - Dilated point.

k - Dilation factor.

By applying this operation, point B becomes point D:

B(x,y) = (0,4), D(x,y) = (0,6)

D(x,y) = (0,0) + k\cdot [(0,4)- (0,0)]

D(x,y) = (0,0) + k\cdot (0,4)

(0,6) = (0,0) +(0,4\cdot k)

(0, 6) = (0,4\cdot k)

k = \frac{3}{2}

Lastly, we transform point C into point E by applying the same operation: C(x,y) = (3, 0), O(x,y) = (0,0) and k = \frac{3}{2}

E(x,y) = (0,0) + \frac{3}{2}\cdot [(3,0)-(0,0)]

E(x,y) = \left(\frac{9}{2}, 0 \right)

The coordinates of E are E(x,y) = \left(\frac{9}{2}, 0 \right).

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3 years ago
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3 - 1/8a = 1/4

The goal is to isolate "a" and its coefficient to make the simplification process easier.

Start by subtracting 3 from both sides:

3 - 3 - 1/8a = 1/4 -3

-1/8a = 1/4 - 3

Next, multiply 3 by 4/4 to convert it into a fraction:

-1/8a = 1/4 - [3 • (4/4)]

-1/8a = 1/4 - 12/4

-1/8a = - 11/4

Multiply both sides by -8:

(-8) -1/8a = - 11/4 (-8)

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