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Mashutka [201]
3 years ago
6

What is the length of segment AB? (4 points)

Mathematics
1 answer:
Sveta_85 [38]3 years ago
3 0

Answer:

10 units

Step-by-step explanation:

\sqrt{(0-6)^{2} +(10-2)^{2} }\\\\\sqrt{(-6)^{2}+(8)^{2} } \\\\\sqrt{36+64}\\\\\sqrt{100}\\\\10

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If you take the square root of an equation to solve, how many answers do you need​
Pepsi [2]

Answer:

answers depend on the question

Step-by-step explanation:

the question has end to end answer

4 0
3 years ago
Please help me quick ASAP!!!!<br> With all the questions
artcher [175]
1. 1 1/5 
2. 63/100
3. 1 1/8 oz.
4. 3 tenths
5. 4/8 and 3/6

hope that helps.
4 0
3 years ago
Read 2 more answers
I need help <br><br> Evaluate functions from their graph
andreev551 [17]

Answer:

g(7)=4

Step-by-step explanation:

We look for where x=7. The way you find the answer is first, find the point (0, 7). Draw a line straight up and down, and see where that line intersects the function. Those intersection points are your answer(there will always be only 1 for a function, but if a graph isn't a function, there might be more than 1).

Using this method here, we see that g(7) intersects our line at (7, 4), so g(7)=4.

6 0
3 years ago
A plumber and his assistant work together to replace the pipes in an old house. The plumber charges $30 an hour for his own labo
Korvikt [17]

Answer:

The plumber worked 50 hours, and his assistant worked 25 hours.

Step-by-step explanation:

Since a plumber and his assistant work together to replace the pipes in an old house, and the plumber charges $ 30 an hour for his own labor and $ 20 an hour for his assistant's labor, and the plumber works twice as long as his assistant on this job, and the labor charge on the final bill is $ 2000, to determine how long did the plumber and his assistant work on this job the following calculation must be performed:

40 x 30 + 20 x 20 = 1200 + 400 = 1600

50 x 30 + 25 x 20 = 1500 + 500 = 2000

Therefore, the plumber worked 50 hours, and his assistant worked 25 hours.

6 0
3 years ago
Given: <br> PQ<br> ⊥<br> QR<br> , PR=20,<br> SR=11, QS=5<br> Find: The value of PS.
dlinn [17]

Answer:

The value of the side PS is 26 approx.

Step-by-step explanation:

In this question we have two right triangles. Triangle PQR and Triangle PQS.

Where S is some point on the line segment QR.

Given:

PR = 20

SR = 11

QS = 5

We know that QR = QS + SR

QR = 11 + 5

QR = 16

Now triangle PQR has one unknown side PQ which in its base.

Finding PQ:

Using Pythagoras theorem for the right angled triangle PQR.

PR² = PQ² + QR²

PQ = √(PR² - QR²)

PQ = √(20²+16²)

PQ = √656

PQ = 4√41

Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.

Finding PS:

Using Pythagoras theorem, we have:

PS² = PQ² + QS²

PS² = 656 + 25

PS² = 681

PS = 26.09

PS = 26

7 0
3 years ago
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