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2 years ago

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emma wants a barbie doll that cost $7.00 . she had only $3.29. how many more money she needs to buy a barbie? use estimate to so

lve the problem.

1 answer:

d1i1m1o1n [39]2 years ago

4 0

Round $3.29 to $3. Then subtract $7 and $3 to get $4

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Need help will give 15 points

Fantom [35]

Answer:

y = -2/3x + 6

Step-by-step explanation:

To find the slope, find how much y changes in proportion to x. Here, when x changes by 1, y changes by -2/3. So, the number before x is -2/3.

To find the y-intercept, we need to find what y will be when x is 0. Since we know that when x is 1, y is 16/3, and when x decreases by 1, y increases by 2/3. So, when x is 0, y is 16/3 + 2/3, which is 18/3, or 6.

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3 years ago

The intensity of a light source at a distance is directly proportional to the strength of the source and inversely proportional

jolli1 [7]

Answer:

x= $\frac{16}{\sqrt[3]{2}+1 }$

Step-by-step explanation:

Q= illumination

I = intensity

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Q_total = $\frac{I_1}{d_1^2}+\frac{I_2}{d_2^2}$

= $\frac{I}{x^2}+\frac{2I}{(16-x)^2}$

now Q' = 0

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x= $\frac{16}{\sqrt[3]{2}+1 }$

[/tex] $\frac{1}{x^3} = \frac{2}{(16-x)^3}$

x= $\frac{16}{\sqrt[3]{2}+1 }$

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2 years ago

There are 4 pitchers.

Westkost [7]

Answer:

7.2 litters of milk

Step-by-step explanation:

4 times 1.8

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3 years ago

Read 2 more answers

What is 1 fifth divided by 6

IgorC [24]

1/5 divided by 6

6 = 6/1

When dividing fractions, we follow a rule called "Keep, change, flip."

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3 years ago

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A sandbox has an area of 10 2/3 square feet, and the length is 1/4 feet. What is the width of the sandbox?

AlekseyPX

Answer:

The width of the sandbox is $42\frac{2}{3} \ ft$ .

Step-by-step explanation:

Given,

Area of the sandbox = $10\frac{2}{3}=\frac{32}{3}\ ft^2$

Length = $\frac{1}{4}\ ft$

Solution,

Let the width of the sandbox be 'w'.

Since the sandbox is in shape of rectangle.

So we use the formula of area of rectangle.

$Area = Length\times Width$

On substituting the given values, we get;

$\frac{1}{4}\times w=\frac{32}{3}\\$

By cross multiplication method, we get;

$w=\frac{32\times4}{3\times 1} =\frac{128}{3} =42\frac{2}{3} \ ft$

Hence The width of the sandbox is $42\frac{2}{3} \ ft$ .

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3 years ago