The interquartile range is affected by the existence of an outliner
Answer:
Please check the explanation.
Step-by-step explanation:
Given
f(x) = 3x + x³
Taking differentiate



solving






now solving




Thus, the expression becomes


Thus,
f'(x) = 3 + 3x²
Given that f'(x) = 15
substituting the value f'(x) = 15 in f'(x) = 3 + 3x²
f'(x) = 3 + 3x²
15 = 3 + 3x²
switch sides
3 + 3x² = 15
3x² = 15-3
3x² = 12
Divide both sides by 3
x² = 4



Thus, the value of x will be:

I think its A. but im not really sure sorry
Answer:
If you mean he starts at 1 on the Y axis (vertical line), then the answer is (1, 3). If you mean he starts at 1 on the X axis (horizontal line), then the answer is (0, 4)
B 2/10 is not simplified because you can divide each number by 2 reducing it to 1/5.