If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
Answer:6
Step-by-step explanation:solve the equation, you know that it equals 90 because the angle is 90
so 16x-6=90
+6 both sides
16x=96
divided by 16 both sides to isolate x
x=6
The answer would be 11/14
Answer:
Im not sure but i think the answer is 0
