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ArbitrLikvidat [17]
3 years ago
8

A homeowner wants to replace their old heating system. Energy is measured in

Mathematics
1 answer:
Studentka2010 [4]3 years ago
6 0

Answer:

1. The A-grid solar panels.

2. It would take 168 days.

Step-by-step explanation:

Let me guess. You got this from Edmentum.

<h2><u><em>PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
You might be interested in
10. Is it possible to draw a three-sided figure where two of the sides are equivalent and two of the angles
Goryan [66]
The anwser is no its not possible
5 0
3 years ago
Simplify the expression (4x − 3)(x + 5). 4x2 − 17x + 15 4x2 − 17x − 15 4x2 + 17x + 15 4x2 + 17x − 15
DanielleElmas [232]
There are mnemonic acronyms out there for reminding you how to do this. I think of it simply as using the distributive property.
  (4x-3)(x+5) = 4x(x+5) -3(x+5)
then again
  = (4x² +20x) + (-3x -15)
  = 4x² + (20-3)x -15 . . . . . . . combine like terms
  = 4x² +17x -15
5 0
3 years ago
Read 2 more answers
Jose earned 50 points in a video game. He lost 45 points, earned 87 points, then lost 25 more points. Enter and evaluate an expr
Olin [163]

Answer:

50-45+87-25=67

Step-by-step explanation:

earning is + so +50

losing is - so  -45

+87

-25

7 0
2 years ago
There are three boxes: one with two golden coins, one with two silver coins, and one with one golden coin and one silver coin. A
krek1111 [17]

Answer:

Step-by-step explanation:

From Bayes' theorem is stated mathematically as the following equation:[2]

{\displaystyle P(A\mid B)={\frac {P(B\mid A)\,P(A)}{P(B)}},}

where A and B are events and P(B) ≠ 0.

P(A) and P(B) are the probabilities of observing A and B without regard to each other.

P(A | B), a conditional probability, is the probability of observing event A given that B is true.

P(B | A) is the probability of observing event B given that A is true.

At this point, go through the attached file before you continue with part B.

Part B)

P(silver) = P(silver from SS)+P(silver from GS)

note P(SS)=P(GG)=P(GS) = 1/3

P(silver from SS) = 1

P(silver from GS) = 1/2

hence

P(Silver from SS) = 1/3

P(Silver from GS) = 1/3 *1/2

P(Silver) = 1/3*1+1/3*1/2

required probability = P(Silver from SS)/P(Silver) = 2/3

4 0
3 years ago
If a coin is tossed 5 times, and then a standard six-sided die is rolled 4 times, and finally a group of three cards are drawn f
Step2247 [10]

Answer:  5,499,187,200

<u>Step-by-step explanation:</u>

A coin is tossed 5 times.  

There are two options (heads or tails) so the possible outcomes are: 2⁵

A six-sided die is rolled 4 times.

There are six options so the possible outcomes are: 6⁴

A group of 3 cards are drawn (without replacement).

The first outcome has 52 options, the second has 51 options, and the third has 50 options: 52 x 51 x 50

Now if we want the coin AND the die AND the cards, we have to multiply all of their possible outcomes:

     2⁵ x   6⁴  x  52 x 51 x 50

=   32 x 1296 x 132,600

=  5,499,187,200

3 0
3 years ago
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