C=2pir
20pi=2pir
20pi/2pi=2pir/2pi
R=10
Height=10/2=5
Two circles surface areas is
2*pir^2
2pi10^2
2*100pi
200pi
The cylindrical part is
2pirh
2pi*10*5
100pi
Add 100pi+200pi=300pi
Answer:
25
Step-by-step explanation:
he got an 80 so if that was his grade by answering 20 questions right then the correct answer would be 25 questions
So the answer is (2c – 3) (2c – 3) or (2c – 3)^2
Answer:
You didn't add a link or an image or anything...
Step-by-step explanation: