1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Annette [7]
3 years ago
9

Omar has a new credit card. He earns 300 reward points for every 100 dollars he spends. If Omar earned 1800 reward points, how m

uch money did he spend?
Mathematics
2 answers:
vazorg [7]3 years ago
6 0

Answer:

He earned 1800 reward points for 600 dollars

Step-by-step explanation:

Given the statement: Omar has a new credit card. He earns 300 reward points for every 100 dollars he spends. If Omar earned 1800 reward points.

Unit rate are expressed as a quantity of 1, such as 3 feet per second or 4 miles per hour, they are called unit rates.

Earn  300 reward point for every 100 dollars.

⇒ unit rate per reward = \frac{100}{300} dollars

we have to find how many dollars he earned for 1800 points.

Number of dollars = unit rate \times 1800

                                 = \frac{100}{300} \times 1800 = 600

Therefore, he earned 1800 reward points for 600 dollars

Cerrena [4.2K]3 years ago
5 0

Answer:

$600 money Omar spends .

Step-by-step explanation:

As given

Omar has a new credit card.

He earns 300 reward points for every 100 dollars he spends.

i.e

300 reward points for every 100 dollars .

Let  us assume that the Omar earned 1800 reward points when he spends x money.

Than the equation becomes

x = \frac{1800\times 100}{300}

x = \frac{1800}{3}

x = $600

Therefore $600 money Omar spends .



   



You might be interested in
Calculus 3 help please.​
Reptile [31]

I assume each path C is oriented positively/counterclockwise.

(a) Parameterize C by

\begin{cases} x(t) = 4\cos(t) \\ y(t) = 4\sin(t)\end{cases} \implies \begin{cases} x'(t) = -4\sin(t) \\ y'(t) = 4\cos(t) \end{cases}

with -\frac\pi2\le t\le\frac\pi2. Then the line element is

ds = \sqrt{x'(t)^2 + y'(t)^2} \, dt = \sqrt{16(\sin^2(t)+\cos^2(t))} \, dt = 4\,dt

and the integral reduces to

\displaystyle \int_C xy^4 \, ds = \int_{-\pi/2}^{\pi/2} (4\cos(t)) (4\sin(t))^4 (4\,dt) = 4^6 \int_{-\pi/2}^{\pi/2} \cos(t) \sin^4(t) \, dt

The integrand is symmetric about t=0, so

\displaystyle 4^6 \int_{-\pi/2}^{\pi/2} \cos(t) \sin^4(t) \, dt = 2^{13} \int_0^{\pi/2} \cos(t) \sin^4(t) \,dt

Substitute u=\sin(t) and du=\cos(t)\,dt. Then we get

\displaystyle 2^{13} \int_0^{\pi/2} \cos(t) \sin^4(t) \, dt = 2^{13} \int_0^1 u^4 \, du = \frac{2^{13}}5 (1^5 - 0^5) = \boxed{\frac{8192}5}

(b) Parameterize C by

\begin{cases} x(t) = 2(1-t) + 5t = 3t - 2 \\ y(t) = 0(1-t) + 4t = 4t \end{cases} \implies \begin{cases} x'(t) = 3 \\ y'(t) = 4 \end{cases}

with 0\le t\le1. Then

ds = \sqrt{3^2+4^2} \, dt = 5\,dt

and

\displaystyle \int_C x e^y \, ds = \int_0^1 (3t-2) e^{4t} (5\,dt) = 5 \int_0^1 (3t - 2) e^{4t} \, dt

Integrate by parts with

u = 3t-2 \implies du = 3\,dt \\\\ dv = e^{4t} \, dt \implies v = \frac14 e^{4t}

\displaystyle \int u\,dv = uv - \int v\,du

\implies \displaystyle 5 \int_0^1 (3t-2) e^{4t} \,dt = \frac54 (3t-2) e^{4t} \bigg|_{t=0}^{t=1} - \frac{15}4 \int_0^1 e^{4t} \,dt \\\\ ~~~~~~~~ = \frac54 (e^4 + 2) - \frac{15}{16} e^{4t} \bigg|_{t=0}^{t=1} \\\\ ~~~~~~~~ = \frac54 (e^4 + 2) - \frac{15}{16} (e^4 - 1) = \boxed{\frac{5e^4 + 55}{16}}

(c) Parameterize C by

\begin{cases} x(t) = 3(1-t)+t = -2t+3 \\ y(t) = (1-t)+2t = t+1 \\ z(t) = 2(1-t)+5t = 3t+2 \end{cases} \implies \begin{cases} x'(t) = -2 \\ y'(t) = 1 \\ z'(t) = 3 \end{cases}

with 0\le t\le1. Then

ds = \sqrt{(-2)^2 + 1^2 + 3^2} \, dt = \sqrt{14} \, dt

and

\displaystyle \int_C y^2 z \, ds = \int_0^1 (t+1)^2 (3t+2) \left(\sqrt{14}\,ds\right) \\\\ ~~~~~~~~ = \sqrt{14} \int_0^1 \left(3t^3 + 8t^2 + 7t + 2\right) \, dt \\\\ ~~~~~~~~ = \sqrt{14} \left(\frac34 t^4 + \frac83 t^3 + \frac72 t^2 + 2t\right) \bigg|_{t=0}^{t=1} \\\\ ~~~~~~~~ = \sqrt{14} \left(\frac34 + \frac83 + \frac72 + 2\right) = \boxed{\frac{107\sqrt{14}}{12}}

8 0
1 year ago
daniel is using a scale factor of 10 to enlarge a class photo that measures 3.5 inches by 5 inches what are The dimensions Love
Sholpan [36]
35 inches by 50 inches
6 0
3 years ago
How many sides does the polygon have?<br> 8<br> 10<br> 12<br> 15
Lynna [10]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
What does 21÷3+(3×9)×9+5 equal? show work below plz
igor_vitrenko [27]
3x9=27
21/3 = 7
so
7+27x9+5
27x9=243
243+7+5
answer is 255
6 0
3 years ago
Read 2 more answers
A vehicle uses 1 1/8 gallons of gasoline to travel 13 1/2 miles. At this rate, how many miles can the vehicle travel per gallon
Vesna [10]
We know that
<span>1 1/8 gallons----------> (1*8+1)/8-------> 9/8 gallons
</span><span>13 1/2  miles----------> (13*2+1)/2-------> 27/2 miles

if 9/8 gallons-------------------> 27/2 miles
 1 gallons----------------------> X
X=(27/2)/(9/8)---------> 216/18--------> 12 miles

the answer is 12 miles</span>
6 0
3 years ago
Read 2 more answers
Other questions:
  • Which could be the resulting equation when elimination is used to solve the given system of equations?
    11·1 answer
  • Find the simple interest for each principle,rate,and time.Round to the hundredths place
    14·1 answer
  • How is solving a problem about constant speed similar to solving a problem about unit price?
    5·1 answer
  • Julina is planninf a 1224-mile driving trip. Her car gets an average of 34 mpg, and the cost of gas is about $3.56/gallon. What
    7·1 answer
  • Is the LCM of a pair of numbers ever equal to one of the numbers?
    6·1 answer
  • What is the value of b
    8·2 answers
  • Lydia drove 216 miles and used 6 gallons of gasoline on a recent trip. Which of the following represents the unit rate of gasoli
    13·2 answers
  • I need to find angle FEG!
    10·1 answer
  • Which statement are true regarding undefinable terms in geometry
    14·1 answer
  • Let's say you want to know how many pages your 10 favorite books have. After checking
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!