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ryzh [129]
4 years ago
15

What is the equation in slope-intercept form of the line that passes through the points(-4,2) and (12,6)?

Mathematics
1 answer:
BlackZzzverrR [31]4 years ago
8 0

Answer:

A

Step-by-step explanation:

Slope intercept form is y = mx + b

First find the slope or m with this equation \frac{y2 - y1}{x2 - x1} (plug in) \frac{6 - 2}{12 + 4} = \frac{4}{16}=  \frac{1}{4}

So your slope is \frac{1}{4}

To find the y-intercept you use y= mx + b and plug in.

6 = 1/4(12) + b

6 = 3 + b (minus 3 on both sides)

3 = b

so 3 is the y-intercept

So the answer is A.

You might be interested in
How many sequences of 0s and 1s of length 19 are there that begin with a 0, end with a 0, contain no two consecutive 0s, and con
sladkih [1.3K]

65 sequences.

Lets solve the problem,

The last term is 0.

To form the first 18 terms, we must combine the following two sequences:

0-1 and 0-1-1

Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent

So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:

2x + 3y = 18

Case 1: x=9 and y=0

Number of ways to arrange 9 identical 2-term sequences = 1

Case 2: x=6 and y=2

Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28

Case 3: x=3 and y=4

Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35

Case 4: x=0 and y=6

Number of ways to arrange 6 identical 3-term sequences = 1

Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65

Hence the number of sequences are 65.

Learn more about Sequences on:

brainly.com/question/12246947

#SPJ4

8 0
2 years ago
Answer C and D please
DENIUS [597]

Answer:

C. solution:

3(3c-2) = 5(2c-1)

or, 9c-6 = 10c-5

or, -6+5 =<em> </em>10c-9c

or, -1 = 1c

Hence, c = -1.

D. solution:

5(5-2a) = 4(6-a)

or, 25-10a = 24 - 4a

or, 25-24 = -4a+10a

or, 1 = 6a

or, 1/6 = a

Hence, a = 1/6.

6 0
3 years ago
Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).
fomenos

Answer:

\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is 2a=|4--10|.

\implies 2a=|14|

\implies 2a=14

\implies a=7

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is (\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)

We need to use the relation a^2+b^2=c^2 to find b^2.

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

c=|6--3|=9

\implies 7^2+b^2=9^2

\implies b^2=9^2-7^2

\implies b^2=81-49

\implies b^2=32

We substitute these values into the standard equation of the hyperbola to obtain:

\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1

\frac{(x+3)^2}{49} -\frac{(y-6)^2}{32}=1

7 0
3 years ago
how much money will you have in 10 years if you invest $12,000 at a 3.3% annual rate of interest compounded quarterly?
Andrej [43]

Answer:

The amount is $16718.7 and the interest is $4718.7.

Step-by-step explanation:

STEP 1: To find amount we use formula:

A=P(1+rn)n⋅t

A = total amount

P = principal or amount of money deposited,

r = annual interest rate

n = number of times compounded per year

t = time in years

In this example we have

P=$12000 , r=3.33% , n=4 and t=10 years

After plugging the given information we have

AAAA=12000(1+0.03334)4⋅10=12000⋅1.00832540=12000⋅1.393225=16718.7

STEP 2: To find interest we use formula A=P+I, since A=16718.7 and P = 12000 we have:

A16718.7II=P+I=12000+I=16718.7−12000=4718.7

4 0
4 years ago
Avni designs a game in which a player either wins or loses 4 points during each turn. Which equation represents all numbers of p
Ierofanga [76]

Answer:

C |p| = 4

Step-by-step explanation:

If a player wins 4points during each turn, then, the total points will be +4points

If the player looses 4points, total points lost will be -4points

The total number of point p the player can have will be represented as;

|p| = 4 (since is both positive and negative 4 )

Note that the nodulus of a variable will return both positive and negative value of that variable

6 0
3 years ago
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