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liraira [26]
2 years ago
10

How many sequences of 0s and 1s of length 19 are there that begin with a 0, end with a 0, contain no two consecutive 0s, and con

tain no three consecutive 1s
Mathematics
1 answer:
sladkih [1.3K]2 years ago
8 0

65 sequences.

Lets solve the problem,

The last term is 0.

To form the first 18 terms, we must combine the following two sequences:

0-1 and 0-1-1

Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent

So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:

2x + 3y = 18

Case 1: x=9 and y=0

Number of ways to arrange 9 identical 2-term sequences = 1

Case 2: x=6 and y=2

Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28

Case 3: x=3 and y=4

Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35

Case 4: x=0 and y=6

Number of ways to arrange 6 identical 3-term sequences = 1

Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65

Hence the number of sequences are 65.

Learn more about Sequences on:

brainly.com/question/12246947

#SPJ4

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The speed of the boat will be 10 mph in still water
4 0
2 years ago
A family of 2 adults and 3 children went on holiday to Miami.
oksano4ka [1.4K]

Answer:

£175

Step-by-step explanation:

Given the exchange rate was £1 = 1.84 dollars.

We are to change 322 dollars to pounds (£).

£1 = 1.84 dollars.

x = 322 dollars

Cross multiply

1.84 * x = 322

1.84x = 322

x = 322/1.84

x = 175

Hence 322 dollars in pounds will be £175

3 0
3 years ago
It is advertised that the average braking distance for a small car traveling at 65 miles per hour equals 120 feet. A transportat
Mrrafil [7]

Answer:

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 120 or not, the system of hypothesis would be:  

Null hypothesis:\mu = 120  

Alternative hypothesis:\mu \neq 120  

Part 2

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{114-120}{\frac{22}{\sqrt{36}}}=-1.636    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z  

Step-by-step explanation:

Data given and notation  

\bar X=114 represent the sample mean  

\sigma=22 represent the population standard deviation

n=36 sample size  

\mu_o =120 represent the value that we want to test

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part 1

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is equal to 120 or not, the system of hypothesis would be:  

Null hypothesis:\mu = 120  

Alternative hypothesis:\mu \neq 120  

If we analyze the size for the sample is > 30 and we  know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part 2

Calculate the statistic

We can replace in formula (1) the info given like this:  

z=\frac{114-120}{\frac{22}{\sqrt{36}}}=-1.636    

P-value

Since is a two sided test the p value would be:  

p_v =2*P(z  

8 0
2 years ago
Please Help!!!!!!<br> I need the answer ASAP!
Evgesh-ka [11]
Bro use Socratic that will help you.
6 0
2 years ago
What is the greatest common factors of 60w,34w^2,and 24w^4
andrew11 [14]

Answer: 2w

Step-by-step explanation:

The greatest common factor could also be referred to as the Highest common factor. Now

60w, 34w² and 24w⁴

Now let concert each to its factors

60 = 2 × 2 × 3 × 5 × w

34w² = 2 × 17 × w × w

24w⁴ = 2 × 2 × 2 × 3 × w × w × w × w

Therefore H.C.F or the greatest common factor

G.C.F = 2 × w

= 2w

4 0
3 years ago
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