We have the representation of this problem in the figure below. As we have a 10.3 mile race, then the equation is fulfilled as:

We know that there is <span>a water station that is twice as far from the starting line as from the finish line, then:
</span>

So:

∴

and

<span>Finally, the distance of the runner from the finish line is:
</span>
Your answer is:
15 litters increased by 60% is 24 litters
Answer:let the invstmt be X and Y
X+Y=34000
0.02X+0.03Y=890
0.02(34000-Y)+0.03Y=890
680-0.02Y+0.03Y=890
0.01Y=210
Y=21000
X=13000
Step-by-step explanation:
Answer: 36
Explanation:
h(x) = 4x^2
Find h(3):
Simply plug x = 3 in the function:
h(3) = 4(3)^2
h(3) = 4(9)
h(3) = 36