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wariber [46]
3 years ago
15

Hank has a bottle of diluted syrup that is 60% maple syrup and a bottle of pure syrup that is 100% maple syrup in his restaurant

. How many ounces of pure syrup should he mix with the diluted syrup in order to make 100 ounces of 85% maple syrup? Express your answer as a decimal rounded to the nearest hundredth if necessary.
Mathematics
1 answer:
Nezavi [6.7K]3 years ago
3 0

9514 1404 393

Answer:

  62.5 oz of 100%

Step-by-step explanation:

Let p represent the number of ounces of pure syrup. Then (100-p) is the number of ounces of 60% syrup. The amount of maple syrup in the desired mix is ...

  p +0.60(100 -p) = 0.85(100)

  0.40p +60 = 85 . . . . . . . . . . . simplify

  0.40p = 25 . . . . . . . . . . subtract 60

  p = 62.5 . . . . . . . . . divide by 0.4

62.5 ounces of pure syrup should be mixed with the diluted syrup to make 100 ounces of 85% maple syrup.

_____

The other 37.5 ounces will be 60% syrup.

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7 0
3 years ago
3. The Food Marketing Institute shows that 17% of households spend more than $100 per week on groceries. Assume the population p
damaskus [11]

Answer:

A)sample proportion = 0.17,  the sampling distribution of p can be calculated/approximated with normal distribution of sample proportion = 0.17 and standard error/deviation = 0.013281

B) 0.869

C)0.9668

Step-by-step explanation:

A) p ( proportion of population that spends more than $100 per week) = 0.17

sample size (n)= 800

the sample proportion of p = 0.17

standard error of p = \sqrt{\frac{p(1-p)}{n} } = 0.013281

the sampling distribution of p can be calculated/approximated with

normal distribution of sample proportion = 0.17 and standard error/deviation = 0.013281

B) probability that the sample proportion will be +-0.02 of the population proportion

= p (0.17 - 0.02 ≤ P ≤ 0.17 + 0.02 ) = p( 0.15 ≤ P ≤ 0.19)

z value corresponding to P

Z = \frac{P - p}{standard deviation}

at P = 0.15

Z =  (0.15 - 0.17) / 0.013281 = = -1.51

at P = 0.19

z = ( 0.19 - 0.17) / 0.013281 = 1.51

therefore the required probability will be

p( -1.5 ≤ z ≤ 1.5 ) = p(z ≤ 1.51 ) - p(z ≤ -1.51 )

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C) for a sample (n ) = 1600

standard deviation/ error = 0.009391 (applying the equation for calculating standard error as seen in part A above)

therefore the required probability after applying

z = \frac{P-p}{standard deviation} at p = 0.15 and p = 0.19

p ( -2.13 ≤ z ≤ 2.13 ) = p( z ≤ 2.13 ) - p( z ≤ -2.13 )

                               = 0.9834 - 0.0166 = 0.9668

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