Answer:
A, B, C, and D, all options are correct.
A is correct because,
∠2 and ∠3 are corresponding angles.
B is correct because,
∠5 and ∠7 are corresponding angles.
C is correct because,
∠2 and ∠4 are corresponding angles.
D is correct because,
∠5 and ∠6 are alternate interior angles.
Note,
If two lines parallel, then
- Corresponding angles are equal.
- Alternate interior angles are equal.
Answer:
(1, 7 )
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Then the equations of the 2 lines are
y = 4x + 3 → (1)
y = 6x + 1 → (2)
Substitute y = 6x + 1 into (1)
6x + 1 = 4x + 3 ( subtract 4x from both sides )
2x + 1 = 3 ( subtract 1 from both sides )
2x = 2 ( divide both sides by 2 )
x = 1
Substitute x = 1 into either of the 2 equations for corresponding value of y
Substituting into (1)
y = 4(1) + 3 = 4 + 3 = 7
Point of intersection = (1, 7 )
Answer:
The solution of given problem is k = 11
Step-by-step explanation:
<u>slope of given two points formula:-</u>
slope m = 
.....(1)
Given points are (1,3) and (5,k)
given slope m = 2
now substituting m =2 and the given points are (1,3) and (5,k)
on simplification we get solution
Answer:
minimum = $445
median = $565
standard deviation = $38
IQR = $48
Step-by-step explanation:
The minimum and the median are measures of location and are affected during addition (or subtraction) and multiplication (or division).
Satandard deviation and IQR (inter-quartile range), which are measures of dispersion, are affected by only multiplication (or division).
For the weight,
<em>minimum </em>= 920 pounds
<em>median </em>= 1160 pounds
<em>standard deviation</em> = 76 pounds
<em>IQR </em>= 96 pounds
For the price,
<em>minimum </em>= 0.50(920) - 15 = $445
<em>median </em>= 0.50(1160) - 15 = $565
<em>standard deviation</em> = 0.50(76) = $38............(<em>Subtraction discarded</em>)
<em>IQR </em>= 0.50(96) = $48........................................(<em>Subtraction discarded</em>)
= 4
= -6
HOPE THIS HELP ^_^
