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umka2103 [35]
2 years ago
13

6x + 12 + 2x - 4 Can u help me pls

Mathematics
1 answer:
Ray Of Light [21]2 years ago
3 0

Answer:

8x+8

Step-by-step explanation:

6x+2x=8x      12-4=8

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Quadrilateral abcd a(-9-6), B(-4-6), c(-3-2), and D(-8-2)
Katen [24]

Step-by-step explanation:

this is the answer

the quadrilateral thus formed is parallelogram

7 0
3 years ago
HURRY<br> What is the volume of this rectangles prism??
kotykmax [81]

The answer is c 400 because 10 times 5 is 50 time 8 equall 400

Step-by-step explanation:

8 0
3 years ago
What is the slope of the line that contains these points?<br> x 31 36 41 46<br> y 10 8 6 4
ankoles [38]

Answer:

-2/5

Step-by-step explanation:

The slope of the line can be found by

m= (y2-y1)/(x2-x1)

  = (8-10)/(36-31)

   = -2/5

4 0
2 years ago
Help- ASAP please (25 points)
Alina [70]

Answer:

(t^2 -4) (t^2 +4)

(t-2)(t+2)(t^2+4)

Step-by-step explanation:

t^4 - 16

We can write this as the difference of squares

We know the dfference of squares is

(a^2 - b^2) = (a-b) (a+b)

( t^2 ^2 - 4^2) = (t^2 -4) (t^2 +4)

We can write t^2 -4 as the difference of squares

t^2 -4 = t^2 -2^2 = (t-2)(t+2)

Replacing this in

( t^2 ^2 - 4^2) = (t^2 -4) (t^2 +4) =  (t-2)(t+2)(t^2+4)

8 0
3 years ago
Read 2 more answers
How to solve this trigonometric equation cos3x + sin5x = 0
mrs_skeptik [129]

Answer:

  x = {nπ -π/4, (4nπ -π)/16}

Step-by-step explanation:

It can be helpful to make use of the identities for angle sums and differences to rewrite the sum:

  cos(3x) +sin(5x) = cos(4x -x) +sin(4x +x)

  = cos(4x)cos(x) +sin(4x)sin(x) +sin(4x)cos(x) +cos(4x)sin(x)

  = sin(x)(sin(4x) +cos(4x)) +cos(x)(sin(4x) +cos(4x))

  = (sin(x) +cos(x))·(sin(4x) +cos(4x))

Each of the sums in this product is of the same form, so each can be simplified using the identity ...

  sin(x) +cos(x) = √2·sin(x +π/4)

Then the given equation can be rewritten as ...

  cos(3x) +sin(5x) = 0

  2·sin(x +π/4)·sin(4x +π/4) = 0

Of course sin(x) = 0 for x = n·π, so these factors are zero when ...

  sin(x +π/4) = 0   ⇒   x = nπ -π/4

  sin(4x +π/4) = 0   ⇒   x = (nπ -π/4)/4 = (4nπ -π)/16

The solutions are ...

  x ∈ {(n-1)π/4, (4n-1)π/16} . . . . . for any integer n

5 0
2 years ago
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