Analyzing a Graph:

J(x) = 3 – x; j(x) = -5

Inessa05 [86]

Answer:

x = 8

Step-by-step explanation:

If j(x) = -5

j(x) = 3 - x

-5 = 3 - x

x = 3 + 5

x = 8

7 0

3 years ago

A swimming pool had 2.5 million liters of water in it. Some water evaporated, and then the pool only had 2 million liters of wat

Phoenix [80]

Answer:

20%

Step-by-step explanation:

8 0

3 years ago

What is 0.235 in expanded form

Ipatiy [6.2K]

Standard Form:
0.235

Expanded Notation Form:

0
+ 0.2
+0.03
+0.005

Expanded Factors Form:
0 * 1
+ 2 * 0.1
+ 3 * 0.01
+ 5 * 0.001

Expanded Exponential Form:
0 * 10^0
+ 2 * 10^-1
+ 3 * 10^-2
+ 5 * 10^-3

Word Form:
Two hundred thirty - five thousandths

Hope that helps!!!

7 0

3 years ago

9. Solve the system of equations using substitution.<br>y = 2x - 10<br>y = 4x - 8

krok68 [10]

Since they’re both in standard form and they both say that y is equal to something, you just have to set them up with one another
2x-10=4x-8
Subtract 2x
-10=2x-8
Add 8
-2=2x
Divide by 2
-1=x
x=-1
Check it by inserting it
2(-1)-10=4(-1)-8
-2-10=-4-8
-12=-12
So x=-1 is the answer

3 0

3 years ago

Read 2 more answers

The annual rainfall in a certain region is approximately normally distributed with mean 41.4 inches and standard deviation 5.7 i

stich3 [128]

Complete question :

The annual rainfall in a certain region is approximately normally distributed with mean 41.4 inches and standard deviation 5.7 inches. Round answers to the nearest tenth of a percent. a) What percentage of years will have an annual rainfall of less than 43 inches? b) What percentage of years will have an annual rainfall of more than 39 inches? c) What percentage of years will have an annual rainfall of between 38 inches and 42 inches?

Answer:

0.61053

0.66314

0.26647

Step-by-step explanation:

Given that :

Mean (m) = 41.4 inches

Standard deviation (s) = 5.7 inches

a) What percentage of years will have an annual rainfall of less than 43 inches?

P(x < 43)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (43 - 41.4) / 5.7 = 0.2807017

p(Z < 0.2807) = 0.61053 ( Z probability calculator)

b) What percentage of years will have an annual rainfall of more than 39 inches? c)

P(x > 39)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (39 - 41.4) / 5.7 = −0.421052

p(Z > −0.421052) = 0.66314 ( Z probability calculator)

What percentage of years will have an annual rainfall of between 38 inches and 42 inches?

P(x < 38)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (38 - 41.4) / 5.7 = −0.596491

p(Z < −0.596491) = 0.27545 ( Z probability calculator)

P(x < 42)

USing the relation to obtain the standardized score (Z) :

Z = (x - m) / s

Z = (42 - 41.4) / 5.7 = 0.1052631

p(Z < 0.1052631) = 0.54192 ( Z probability calculator)

0.54192 - 0.27545 = 0.26647

6 0

3 years ago