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kati45 [8]
3 years ago
6

A random number generator is used to select an integer from 1 to 3 inclusive. What is the difference between the estimated proba

bility that a 3 is generated and the actual probability that a 3 is generated?
Mathematics
1 answer:
valentina_108 [34]3 years ago
8 0

Step-by-step Answer:

In general, random number generators generate a uniform distribution, and we generally ASSUME that this is so.

If that is the case, the estimated probability of selecting a 3 is 1/3.

The actual probability depends on the generator.  Some as ASSUMED to be uniform, but it could be biased on particular numbers, knowingly or unknowingly.  

Some generators are programmed to generate particular distributions (other than uniform), such as exponential, normal, or any other probability distribution.  In these cases, the probability of selecting a 3 will depend on the distribution.

Even if the generated distribution is known, the actual probability could still be different from the theoretical (or estimated), because that is why we call them "random numbers".

In short, the "actual" probability depends on the characteristics of the generator, of which we have no knowledge.

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In proving  that C is the midpoint of AB, we see truly that C has Symmetric  property.

<h3>What is the proof about?</h3>

Note that:

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See full question below

Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive

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Math you can get brainly est
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2 years ago
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Step-by-step explanation:

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