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saw5 [17]
3 years ago
12

Please help asap im confused

Mathematics
2 answers:
Alchen [17]3 years ago
8 0

Answer:

Brand #2

Step-by-step explanation:

Brand #2 is the cheapest making it the best value.

Hope this helped :)

tigry1 [53]3 years ago
3 0

Answer:

brand 2

Step-by-step explanation:

brand 2 is 1.18 per packet

You might be interested in
Describe does Glide Reflection from the preimage triangle and black to the image triangle in red
AveGali [126]

Answer:

d

Step-by-step explanation:

Lets look at V which is at (2,-4).

We will also look at it's image V' which is at (-2,-1).

Let's go through the choices:

a. translation left 4 units and down 1 unit reflection x axis

Translating V left 4 and down 1 would give us (2-4,-4-1)

(-2,-5)

Reflecting that across the x-axis would give us

(-2,5).

So this is not (-2,-1) so let's move on...

b. translation left 2 units and up 2 units reflection line x=1

Translating V left 2 and up 2 gives us

(2-2,-4+2)

(0,-2)

Now reflecting this over x=1 gives us

(2,-2). ( Imagine this x=1 which is verical going right smack between points (0,-2) and (2,-2).)

We still did not reach our goal image.

c. translation left 2 units up and up 3 units reflection y axis

Starting at V(2,-4) and moving left 2 & up 3 gives (2-2,-4+3)=(0,-1).

Now reflecting this over the vertical axis, the y-axis, gives us (0,-1).

So we did not reach our (-2,-1) point yet.

d. translation left 2 units and 3 units reflection line x=-1.

​Starting at (2,-4) then moving left 2 and up 3 gives us (2-2,-4+3)=(0,-1).

Now we are reflecting over x=-1 which means we want to choose a point on the side making x=-1 the middle. Thuis point on the other side of (0,-1) of x=-1 would be (-2,-1) which is the goal.

8 0
3 years ago
Match the hyperbolas represented by the equations to their foci.
Arte-miy333 [17]

Answer:

1) (1 , -22) and (1 , 12) ⇔ (y + 5)²/15² - (x - 1)²/8² = 1

2) (-7 , 5) and (3 , 5) ⇔ (x + 2)²/3² - (y - 5)²/4² = 1

3) (-6 , -2) and (14 , -2) ⇔ (x - 4)²/8² - (y + 2)²/6² = 1

4) (-7 , -10) and (-7 , 16) ⇔ (y - 3)²/5² - (x + 7)²/12² = 1

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with

  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1

- the coordinates of the foci are (h ± c , k), where c² = a² + b²

- The standard form of the equation of a hyperbola with

  center (h , k) and transverse axis parallel to the y-axis is

  (y - k)²/a² - (x - h)²/b² = 1

- the coordinates of the foci are (h , k ± c), where c² = a² + b²

* Lets look to the problem

1) The foci are (1 , -22) and (1 , 12)

- Compare the point with the previous rules

∵ h = 1 and k ± c = -22 ,12

∴ The form of the equation will be (y - k)²/a² - (x - h)²/b² = 1

∵ k + c = -22 ⇒ (1)

∵ k - c = 12 ⇒ (2)

* Add (1) and(2)

∴ 2k = -10 ⇒ ÷2

∴ k = -5

* substitute the value of k in (1)

∴ -5 + c = -22 ⇒ add 5 to both sides

∴ c = -17

∴ c² = (-17)² = 289

∵ c² = a² + b²

∴ a² + b² = 289

* Now lets check which answer has (h , k) = (1 , -5)

  and a² + b² = 289 in the form (y - k)²/a² - (x - h)²/b² = 1

∵ 15² + 8² = 289

∵ (h , k) = (1 , -5)

∴ The answer is (y + 5)²/15² - (x - 1)²/8² = 1

* (1 , -22) and (1 , 12) ⇔ (y + 5)²/15² - (x - 1)²/8² = 1

2) The foci are (-7 , 5) and (3 , 5)

- Compare the point with the previous rules

∵ k = 5 and h ± c = -7 ,3

∴ The form of the equation will be (x - h)²/a² - (y - k)²/b² = 1

∵ h + c = -7 ⇒ (1)

∵ h - c = 3 ⇒ (2)

* Add (1) and(2)

∴ 2h = -4 ⇒ ÷2

∴ h = -2

* substitute the value of h in (1)

∴ -2 + c = -7 ⇒ add 2 to both sides

∴ c = -5

∴ c² = (-5)² = 25

∵ c² = a² + b²

∴ a² + b² = 25

* Now lets check which answer has (h , k) = (-2 , 5)

  and a² + b² = 25 in the form (x - h)²/a² - (y - k)²/b² = 1

∵ 3² + 4² = 25

∵ (h , k) = (-2 , 5)

∴ The answer is (x + 2)²/3² - (y - 5)²/4² = 1

* (-7 , 5) and (3 , 5) ⇔ (x + 2)²/3² - (y - 5)²/4² = 1

3) The foci are (-6 , -2) and (14 , -2)

- Compare the point with the previous rules

∵ k = -2 and h ± c = -6 ,14

∴ The form of the equation will be (x - h)²/a² - (y - k)²/b² = 1

∵ h + c = -6 ⇒ (1)

∵ h - c = 14 ⇒ (2)

* Add (1) and(2)

∴ 2h = 8 ⇒ ÷2

∴ h = 4

* substitute the value of h in (1)

∴ 4 + c = -6 ⇒ subtract 4 from both sides

∴ c = -10

∴ c² = (-10)² = 100

∵ c² = a² + b²

∴ a² + b² = 100

* Now lets check which answer has (h , k) = (4 , -2)

  and a² + b² = 100 in the form (x - h)²/a² - (y - k)²/b² = 1

∵ 8² + 6² = 100

∵ (h , k) = (4 , -2)

∴ The answer is (x - 4)²/8² - (y + 2)²/6² = 1

* (-6 , -2) and (14 , -2) ⇔ (x - 4)²/8² - (y + 2)²/6² = 1

4) The foci are (-7 , -10) and (-7 , 16)

- Compare the point with the previous rules

∵ h = -7 and k ± c = -10 , 16

∴ The form of the equation will be (y - k)²/a² - (x - h)²/b² = 1

∵ k + c = -10 ⇒ (1)

∵ k - c = 16 ⇒ (2)

* Add (1) and(2)

∴ 2k = 6 ⇒ ÷2

∴ k = 3

* substitute the value of k in (1)

∴ 3 + c = -10 ⇒ subtract 3 from both sides

∴ c = -13

∴ c² = (-13)² = 169

∵ c² = a² + b²

∴ a² + b² = 169

* Now lets check which answer has (h , k) = (-7 , 3)

  and a² + b² = 169 in the form (y - k)²/a² - (x - h)²/b² = 1

∵ 5² + 12² = 169

∵ (h , k) = (-7 , 3)

∴ The answer is (y - 3)²/5² - (x + 7)²/12² = 1

* (-7 , -10) and (-7 , 16) ⇔ (y - 3)²/5² - (x + 7)²/12² = 1

7 0
3 years ago
The sum of 10 and twice a number<br> (an equation)
Gekata [30.6K]

Answer:

10+2x= the sum (anything could be put here)

Step-by-step explanation:

Well sum is automatically addition

Doubleing a number is basically multiplying it by 2

so

10+2x= whatever youw ant to put here

8 0
2 years ago
The temperature in an oven changes from 350 degrees to 362 degrees. What is the percent increase in temperature, to the nearest
Aleksandr-060686 [28]

Answer:

it's 3.4%

Step-by-step explanation:

You take the difference of 362 and 350 (which is 12) and divide it by the starting number (350) getting you 3.4

5 0
2 years ago
1) The number √ , where n is a prime number is
Firlakuza [10]
It is an irrational number
3 0
3 years ago
Read 2 more answers
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