Answer:
D
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
If m > 0 , then line slopes upwards from left to right
If m < 0 , then line slopes downwards from left to right
y = 3x - 2
has m > 0 and c = - 2 , thus line slopes upwards crossing the y- axis at - 2
y = - 2x + 3
has m < 0 and c = 3, thus line slopes downwards crossing the y- axis at 3
on the graph this is the lower blue line and the red line
the solution to the system is at the point of intersection of the 2 lines
This is at point D
Answer:
(-7, -12)
Step-by-step explanation:
4x-3y=8
5x-2y=-11
Is there any of the like terms can be added and the result will be 0? No, so we have to multiple one OR both of the equations to make that one number do that.
(I will try to remove the y like terms so i will multiple both of them by the opposite so both of the ys will be 6)
2(4x-3y=8)
-3(5x-2y=-11)
8x-6y=16
-15x+6y=33
(now the easy part… cancel the 6s and add the equations)
8x+(-15x)=-7x
16+33=49
-7x=49
(divide 49 by -7)
x=-7
Replace x in any of the equations and you’ll get the y value.
4x-3y=8
4(-7)-3y=8
-28-3y=8
-3y=36
y=12
Threfore, there is one solution which is….. (-7,-12)
Answer:
<u>Residue</u>
Step-by-step explanation:
Let a and b be integers. We define a mod b to be the residue of dividing a by b. For example, if a evenly divides b, then a mod b=0, 20 mod 6= 2. The modulus operator is widely used in programming, and it is convenient when a and b are large numbers.
a mod b is always a nonnegative integer. In fact, 0≤ a mod b≤ |b-1| by the division algorithm. a and b can also be negative integers. Since 8=-(-5)+3 then 8 mod -5= 3.
As a final example, some known properties can be rewritten in terms of mod. a mod 2=0 if and only if a is even. a mod 2=1 if and only if a is odd.
My answer is prob 20 miles......