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ki77a [65]
2 years ago
15

Use the Distance Formula to find the distance between (13, 1) and (9,- 4), rounded to the nearest hundredth.

Mathematics
1 answer:
valina [46]2 years ago
4 0

Answer:

  about 6.40 units

Step-by-step explanation:

The distance formula is ...

  d = √((x2 -x1)^2 +(y2 -y1)^2)

For the given points, the distance between them is ...

  d = √((9 -13)^2 +(-4-1)^2) = √((-4)^2 +(-5)^2) = √(16 +25)

  d = √41 ≈ 6.40

The distance between the points is about 6.40 units.

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A factory buys 10% of its components from suppliers B and the rest from supplier C. It is known that 6% of the components it buy
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Answer:

The percentage of the components bought from supplier C that are faulty = 88%

Complete Question:

A factory buys 10% of its components from supplier A, 30% from supplier B,and the rest from supplier C. it is known that 6% of the components it buys are faulty. of the components bought from supplier A, 9% are faulty and of the components bought from supplier B, 3% are faulty.

find the percentage of the components bought from supplier C that are faulty ?

Step-by-step explanation:

Let x be the total components bought by the factory

Components supplied by A = 10% of x

Components supplied by B = 30% of x

The rest supplied by C:

Percentage supplied by C = 100-(30+10) = 100-40 = 60%

Components supplied by C = 60% of x

% of all faulty components = 6%

Amount of faulty component = 6% of x

faulty components from A= 9%

Amount of faulty component from A= 9% × (6% of x) = 0.0054x

faulty components from B= 3%

Amount of faulty component from A= 3% × (6% of x) = 0.0018x

Amount of faulty component from C = (6% of x) - (0.0054x+0.0018x)

= 0.06x - 0.0072x

= 0.0528x

Let the percentage of the components bought from supplier C that are faulty = y%

y% × 6% of x = 0.0528x

y% × 0.06x = 0.0528x

y% = 0.0528x/0.06x

y% = 0.88 = 88%

The percentage of the components bought from supplier C that are faulty = 88%

3 0
3 years ago
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