Answer:
6%
Step-by-step explanation:
Step 1
The fist step is to define the probabilities.
The events are independent from each other. Each team wins with probability 
and looses with probability 
Let 
be probability that Roses win and 
be the probability that Roses loose.
Step 2
The second step is to calculate the probabilities by multiplying the probabilities with the first 3 terms in the product being the probability of a win and the last term being the probability of a loss.
The calculation is shown below,
Step 3
The last step is to convert this probability into a percentage. Converting this probability to a percentage is done as shown below,
Step 4
The next step is to round down the percentage . The value of 6.25% rounded down is 6%. The correct answer is 6%.
Answer: $1.50
Step-by-step explanation:
Cost price of watermelon = $1.25
Profit percent = 20%
Profit = Profit percent × Cost price
= 20% × $1.25
= 20/100 × $1.25
= 0.2 × $1.25
= $0.25
Selling price = Cost price + Profit
Selling price = $1.25 + $0.25
Selling price = $1.50
They should charge $1.50 for the watermelons
The answer is B. It is increasing by 9 each time.
30% of 42 is 12.6$.
42-12.6 = 29.4$ is the price of the pair with discount applied.
Tax 7%
29.4 * 7% = 2.06
29.4$ + 2.06$ = 31.46 $ final price with discount and tax applied.
Answer:
The distribution of sample proportion Americans who can order a meal in a foreign language is,
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
The standard deviation of this sampling distribution of sample proportion is:
The sample size of Americans selected to disclose whether they can order a meal in a foreign language is, <em>n</em> = 200.
The sample selected is quite large.
The Central limit theorem can be applied to approximate the distribution of sample proportion.
The distribution of sample proportion is,
