Answer:
He missed 10 questions and got 30 right
Step-by-step explanation:
So we could do 0.75 times 40 and we would get 30
So he got 30 questions right which isn't too bad
First figure out how many times 9 can go into 25 **do the highest amount of times it can go in-
<span><span>9x1=9 </span><span>9x2=18 </span><span>9x3=27 </span><span>9x4=<span>36
nine can go in 2 times because 3 times would be way to much
so you're mixed number would be 2
now to figure out you're numerator do 25-18=7
Now it would be 2 7/25
so you're mixed number,then the numerator,finally denomantor ALWAYS stays the same.
*IF YOU'RE NUMERATOR AND DENOMANTOR CAN BE REDUCED THEN REDUCE</span></span></span>
Answer:
Step-by-step explanation:
∛-64 = -4
![\sqrt[3]{m^{15}} =m^5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bm%5E%7B15%7D%7D%20%3Dm%5E5)
∛n³ = <em>n</em>
So average is of the first 6 tests is 82 well that means
(test1 + test2+ test3+ test4 + test5+test6)/6 = 82
so now let do some cross multiplliying
test1 + test2 + test3 + test 4 + test5 +test6 = 82*6
test1 + test2 + test3 + test 4 + test5 +test6 = 492
now lets see if we can find that 7th test score
(test1 + test2 + test3 + test4 + test5 +test6 + test7)/7 = 80.5
So look we found test1 + test2 + test3 + test4 + test5 +test6 to be 492 so lets substitute.
(492 + test7 )/7 = 80.5
test7 = (80.5*7)-492 = 71.5
