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2 years ago

X-3x+3<6 Solve the problems

Mathematics

2 answers:

lys-0071 [83]2 years ago

8 0

Answer:

X>-3/2

Step-by-step explanation:

To start off, you have to get x on one side and the numbers on the other. To do this, subtract 3 on both sides to get the +3 to the other side. After this you should have X-3X<3. Now that you have all the x values on one side, subtract them to get-2X. Now your equation is -2X<3. Now you divide to not have a coefficient before X. To do this divide by -2. Keep in mind that when you divide by a negative number in an inequality, the sign flips. Because of this your answer would be X>-3/2.

bixtya [17]2 years ago

5 0

Answer:

x > -3/2

Step-by-step explanation:

x-3x+3<6

Combine like terms

-2x+3<6

Subtract 3 from each side

-2x +3-3<6-3

-2x <3

Divide each side by -2,remembering to flip the inequality

-2x/-2 > 3/-2

x > -3/2

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trapecia [35]

$\huge \bf༆ Answer ༄$

Let the capacity of bus be x students

And van be y students, now ;

From the given statements we get two equations ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:2x + 10y = 260 \: \: \: \: \: (1)$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:13x + 5y = 670 \: \: \: \: \: (2)$

multiply the equation (2) with 2 [ it won't change the values ]

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:2x + 10y = 260 \: \: \: \: \: \: \: \: \: (1)$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:26x + 10y = 1340 \: \: \: \: \: (3)$

Now, deduct equation (1) from equation (3)

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:26x + 10y - 2x - 10y = 1340 - 260$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:24x = 1080$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x = 1080 \div 24$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x = 45$

Therefore each bus can carry (x) = 45 students

Now, plug the value of x in equation (1) to find y ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:2x + 10y = 260$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:(2 \times 45) + 10y = 260$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:90 + 10y = 260$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:10y = 260 - 90$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:10y = 170$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y = 170 \div 10$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y = 17$

Hence, each van can carry (y) = 17 students in total.

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WINSTONCH [101]

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