All categories

3 years ago

If a coyote could run 44mph and maintain this speed. How far could it run in 15 minutes

Mathematics

1 answer:

jenyasd209 [6]3 years ago

8 0

Answer:

44 miles per hour

44 miles per 60 minutes

44/4 miles per 60/4 minutes

11 miles per 15 minutes

You might be interested in

Urgent help!<br> Simplify (x − 4)(4x^2 + x − 6).

m_a_m_a [10]

Answer:

2X-1

Step-by-step explanation:

as far as i got

6 0

3 years ago

I will give brainliest if you answer all correctly

miskamm [114]

Answer:

I think 13 is C

Step-by-step explanation:

71+52= 123

180-123= 57

7 0

3 years ago

g 78% of all Millennials drink Starbucks coffee at least once a week. Suppose a random sample of 50 Millennials will be selected

Tatiana [17]

Answer:

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

$np=50*0.78=39 \geq 10$

$n(1-p)=50*(1-0.78)=11 \geq 10$

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}})$

With the following parameters:

$\mu_ p = 0.78$

$\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

We know that n = 50 and p =0.78.

We need to check the conditions in order to use the normal approximation.

$np=50*0.78=39 \geq 10$

$n(1-p)=50*(1-0.78)=11 \geq 10$

Since both conditions are satisfied we can use the normal approximation and the distribution for the proportion is given by:

$p \sim N (p, \sqrt{\frac{p(1-p)}{n}})$

With the following parameters:

$\mu_ p = 0.78$

$\sigma_p = \sqrt{\frac{0.78*(1-0.78)}{50}}= 0.0586$

6 0

3 years ago

Quadrilateral CDEF is dilated by a scale factor of į to form quadrilateral C'D'E'F'.

Kobotan [32]

Given:

CDEF is dilated by a scale factor of $\dfrac{3}{4}$ to form the quadrilateral C'D'E'F'.

To find:

The measure of side E'F'.

Solution:

If a figure is dilated by a scale factor of k, then the side of dilated figure is k times of corresponding side of original figure.

CDEF is dilated by a scale factor of $\dfrac{3}{4}$ to form the quadrilateral C'D'E'F'. So,

$E'F'=\dfrac{3}{4}\times EF$

From the given figure it is clear that $EF=12$ . So,

$E'F'=\dfrac{3}{4}\times 12$

$E'F'=9$

Therefore, the measure of side E'F' is 9 units.

7 0

2 years ago

The regression equation for change in temperature, y, to amount of humidity in

mr_godi [17]

Answer:

Residual = 11.462

Since the residual is positive, it means it is above the regression line.

Step-by-step explanation:

The residual is simply the difference between the observed y-value which is gotten from the scatter plot and the predicted y-value which is gotten from regression equation line.

The predicted y-value is given as 20.7°

The regression equation for temperature change is given as;

y^ = 9.1 + 0.6h

h is the observed amount of humidity and it's given to be 23 percent or 0.23.

Thus;

y^ = 9.1 + 0.6(0.23)

y^ = 9.238

Thus:

Residual = 20.7 - 9.238

Residual = 11.462

Since the residual is positive, it means it is above the regression line.

3 0

3 years ago

Read 2 more answers