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S_A_V [24]
2 years ago
14

Multiply: 3x4= and 2 x 3 =

Mathematics
2 answers:
frez [133]2 years ago
5 0

Answer:

3x4=12 2x3=6

Step-by-step explanation:

MakcuM [25]2 years ago
4 0

Answer:

12 and 6

Step-by-step explanation:

3x4 is 12

2x3 is 6

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The quadratic has a vertex of (10,-9) and y-intercept of (0,-4). Write an equation in vertex form. PLZ EXPLAIN!!!!
weeeeeb [17]
Hello there!

Knowing that the vertex form of the quadratic equation is
y=a(x-h)^2+k where (h,k) represents the vertex, and the a value represents the leading coefficient of the quadratic equation in standard form, first plug in your known values (your given coordinate point can be plugged into the x and y values, and your given vertex can be plugged into h and k):
-4=a(0-10)^2-9

Because your a value is still unknown, you can use your given values in the equation to solve for a:
-4=a(-10)^2-9
-4=100a-9
100a=5
a=1/20

Now that you have your a value, you can plug it into your vertex form as well as your vertex values to get that your equation in vertex form is:
y=1/20(x-10)^2-9
3 0
3 years ago
What could this be! Someone please help
Andrei [34K]
Top one would make more sense
8 0
3 years ago
Read 2 more answers
The sum of the measures of two angles is 90° one angle has a measure of 32.8° the other angle is represented by X what is the me
amid [387]

Answer:

x = 57.2

Step-by-step explanation:

Equation:

32.8 + x = 90

x = 90 - 32.8

x = 57.2

8 0
2 years ago
A triangle has sides of 18cm and 32cm. The measurement of the longest side is missing. Ted says that one possibility for the unk
gulaghasi [49]
Since the measurement of the longest side is missing we can use the pythagorean theorem to find the hypotenuse or longest side.

18^2 + 32^2 = c (hypotenuse) ^2
324 + 1,024 = c^2
1,348 = c^2
sqrt 1,348 = c
36.72 = c
i do not agree with ted because when you use the pythagorean theorem you do not get 47cm

this can be proved by
18^2 + 32 ^2 = 47^2
we already know the left side is 1,348
1,348 = 47^2
1,348 does not equal 2,209 which is 47 squared
4 0
3 years ago
Find three consecutive odd integers such that the sum of the largest and twice the smallest is 25. If x represents the smallest
Murrr4er [49]
1. x
2. x + 2
3. x + 4

x + 4 + 2x = 25. Second option is the answer.


Combine like terms
3x + 4 = 25
Subtract 4 from both sides
3x = 21
Divide both sides by 3
x = 7
5 0
3 years ago
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