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ra1l [238]
3 years ago
14

What is the value of x when f(x)=8? A. 1 B. 3 C. 0 D. 2

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
8 0

Answer: 1

Step-by-step explanation:

lesantik [10]3 years ago
4 0
It’s A. Because x will always = (1) unless said other wise so for example
What times what equals 2 1x2=2
Well take away the one day the question is
X times what equals two and you just remember that x always = 1 so 1 times 2 = 2

I hope that helps you understand! Let me know if you have any questions!
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Negative symbol as opposite | HELP PLS
Pepsi [2]

Answer: I would have to say its zero

Sorry if I got it wrong

4 0
2 years ago
Read 2 more answers
Dana has 4 hours to spend training for an upcoming race. She completes her training by running full speed the distance of the ra
Sedaia [141]

Answer:

2hrs 40 minutes

Step-by-step explanation:

The formula for distance is expressed as:

d=st, s=speed, t=time

#The time taken to run:

d=st\\\\t=d/s\\\\t_r=d/8

#The time taken to walk:

d=st\\\\t=d/s\\\\t_w=d/2

#Since the distances are the same:

d_r=8t_r,d_w=2t_w\\\\8t_r=2t_w\\\\t_r+t_w=4->t_w=4-t_r\\\\\therefore8t_r=2(4-t_r)\\\\8t_r=8-2t_r\\\\t_r=1\frac{1}{3} \hrs\\\\t_w=4-1\frac{1}{3}=2\frac{2}{3}\ hrs

Hence, Dana spends 2hrs 40 minutes walking back

8 0
3 years ago
Solve for r.<br><br> 19 = 7 − –3r
FinnZ [79.3K]

Answer:

4

Step-by-step explanation:

19 = 7 + 3r

12 = 3r

4 = r

5 0
3 years ago
Read 2 more answers
Today the price of a Jeep is $25,000. In 1970, the price was $5,000. What's the price relative?
IgorC [24]

Answer:

$500

Step-by-step explanation:

Today the price of a Jeep is $25,000.

In 1970, the price was $5,000.

We need to find the relative price. It can be calculated as follows :

P=\dfrac{25000}{5000}\times 100\\\\P=\$500

So, the relative price is $500.

4 0
3 years ago
What is the solution(s) to the system of equations y = x² +4 and y = 2x + 4
bija089 [108]

Answer:

(x,y) = (0,4)~ \text{and}~ (x,y) = (2,8)

Step by step explanation:

y = x^2 +4~~~~~~~~~...(i)\\\\y = 2x +4~~~~~~~~~...(ii)\\\\\text{From (i) and (ii):}\\\\~~~~~~x^2 +4 = 2x+4\\\\\implies x^2 = 2x\\\\\implies x^2 -2x = 0\\\\\implies x(x-2) = 0\\\\\implies x =0,~ x = 2

\text{Substitute x = 0 in eq (i):}\\\\y = 0^2 +4 = 4\\\\\text{Substitute x = 2 in eq (i):}\\\\y=2^2+4 = 4+4 = 8\\\\\text{Hence,}~ (x,y)= \{(2,8), (0,4)\}

3 0
2 years ago
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