1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
charle [14.2K]
3 years ago
8

Divide. Round to the nearest tenth. 104÷5.1

Mathematics
2 answers:
vlada-n [284]3 years ago
6 0
104 ÷ 5.1 = 20.3921
Nearest tenth 20.4
tatuchka [14]3 years ago
3 0

Answer: 20,4

Step-by-step explanation:

\frac{104}{5.1} = \frac{1040}{51}

First, we take from 1040, only 104 and look up for a number that multiply by 51 gives less or equal 102, so:

51 * 2 = 102, this 2 goes to the answer

and 104 - 102 = 2

And now we use the last zero from 1040, and now we have a 20, but that number is less than 51, so we add another zero to have a 200, and we have to add another zero to the 2 of the answer

So, our answer until now is 20

Now, we add a coma to the answer (20,) and with the 200, we look up for a number that multiply by 51 gives less or equal 200, so:

51 * 3 = 153

And the answer until now is 20,3

and 200-153 = 47

We are in the same case, so we add a zero to get 470 and we look up for a number that multiply by 51 gives less or equal 470, so:

51 * 9 = 459

So the answer so far is 20,39

You might be interested in
A pound of grapes cost $1.98 and a pound of strawberries is $2.45. If I purchased 0.5 pound of grapes and 1.4 pounds of strawber
ozzi

So first let's find the cost of the grapes.

price for half a pound would be half the price. so 1.98/2 = $0.99

then let's find the price for 1.4 pounds of strawberry.

1.4*2.45 = $3.43

now add the answers and you'll get is

= $4.42

6 0
3 years ago
On January 3rd, the Earth is 147,500,000 kilometers away from the Sun. On July 4th, the Earth is 152,500,000 kilometers away fro
11Alexandr11 [23.1K]

Answer:

no

Step-by-step explanation:

yes

4 0
3 years ago
Simplify 3/4-1/3+1/12​
Semenov [28]

Answer: 1/2 I believe :-)

5 0
3 years ago
Read 2 more answers
Write a sine and cosine function that models the data in the table. I need steps to both the sine and cosine functions for a, b,
babymother [125]

Answer(s):

\displaystyle y = -29sin\:(\frac{\pi}{6}x + \frac{\pi}{2}) + 44\frac{1}{2} \\ y = -29cos\:\frac{\pi}{6}x + 44\frac{1}{2}

Step-by-step explanation:

\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 44\frac{1}{2} \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-3} \hookrightarrow \frac{-\frac{\pi}{2}}{\frac{\pi}{6}} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{12} \hookrightarrow \frac{2}{\frac{\pi}{6}}\pi \\ Amplitude \hookrightarrow 29

<em>OR</em>

\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow 44\frac{1}{2} \\ Horisontal\:[Phase]\:Shift \hookrightarrow 0 \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{12} \hookrightarrow \frac{2}{\frac{\pi}{6}}\pi \\ Amplitude \hookrightarrow 29

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of <em>sine</em>, then there WILL be a horisontal shift, meaning that a C-term will be involved. As you can see, the centre photograph displays the trigonometric graph of \displaystyle y = -29sin\:\frac{\pi}{6}x + 44\frac{1}{2},in which you need to replase "cosine" with "sine", then figure out the appropriate C-term that will make the graph horisontally shift and map onto the <em>cosine</em> graph [photograph on the left], accourding to the <u>horisontal shift formula</u> above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY <em>REALLY</em> ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the <em>sine</em> graph [centre photograph] is shifted \displaystyle 3\:unitsto the right, which means that in order to match the <em>cosine</em> graph [photograph on the left], we need to shift the graph BACKWARD \displaystyle 3\:units,which means the C-term will be negative, and by perfourming your calculations, you will arrive at \displaystyle \boxed{3} = \frac{-\frac{\pi}{2}}{\frac{\pi}{6}}.So, the sine graph of the cosine graph, accourding to the horisontal shift, is \displaystyle y = -29sin\:(\frac{\pi}{6}x + \frac{\pi}{2}) + 44\frac{1}{2}.Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph WILL hit \displaystyle [12, 15\frac{1}{2}],from there to the y-intercept of \displaystyle [0, 15\frac{1}{2}],they are obviously \displaystyle 12\:unitsapart, telling you that the period of the graph is \displaystyle 12.Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the <em>midline</em>. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at \displaystyle y = 44\frac{1}{2},in which each crest is extended <em>twenty-nine units</em> beyond the midline, hence, your amplitude. Now, there is one more piese of information you should know -- the cosine graph in the photograph farthest to the right is the OPPOCITE of the cosine graph in the photograph farthest to the left, and the reason for this is because of the <em>negative</em> inserted in front of the amplitude value. Whenever you insert a negative in front of the amplitude value of <em>any</em> trigonometric equation, the whole graph reflects over the <em>midline</em>. Keep this in mind moving forward. Now, with all that being said, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

I am delighted to assist you at any time.

5 0
3 years ago
A waiter earned 5$ per hour at his job plus an additional 60$ in tips on Friday he earned more than 112$ total write an inequali
ycow [4]
5x + 60 > 112 because he earned 5 dollars per hour (x) plus the tips (60) and it was more than (>) 112 dollars.
8 0
3 years ago
Other questions:
  • The expression above can also be written in the form a^b/c
    11·2 answers
  • The area of a rug is 36 one fourth square feet. The rug is 8 three fourths feet long. What is the length of the rug
    14·1 answer
  • Consider the linearization, L(x) of the curve y = x at (36, 6). What are the least and greatest values of x for which this linea
    9·1 answer
  • Find three ordered pairs for the equation y = x – 5 using the chart below.
    14·1 answer
  • I need help!!!! Please
    15·1 answer
  • Which of the following represents the prime factortzation of 72?
    12·1 answer
  • 127 freshman, 63 sophomores, 55 juniors &amp; 55 seniors what is the ratio of freshman to the total number of band members
    15·1 answer
  • Can someone help me?​
    5·1 answer
  • HELP PLEASE ASAP IF NOT RIGHT ANSWER WILL BE REPORTED!!!
    7·2 answers
  • Sinx+(75độ)=sin 15 độ
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!