Answer:
54 sq units
Step-by-step explanation:
The triangle at the top (FAB) has a base of 10 and a height of 3. Area of triangle is 1/2bh so 1/2(10 * 3) = 1/2 * 30 = 15 sq units
If you cut off the triangle you have a trapezoid, EBCD. A trapezoid is (b1 + b2)/2 * h, so (6 + 7)/2 * 6 = 13/2 * 6 = 6.5 * 6 = 39 sq units
Add them together: 15 + 39 = 54 sq units
Answer:
Using the relation between angles and sides of any triangle the answer is:
Third option: WX, XY, YW
Step-by-step explanation:
<X=90° (right angle)
<W=51°
<Y=?
The sum of the interior angles of any triangle is 180°, then:
<W+<X+<Y=180°
Replacing the given values:
51°+90°+<Y=180°
141°+<Y=180°
Solving for <Y: Subtracting 141° both sides of the equation:
141°+<Y-141°=180°-141°
<Y=39°
The order of the angles from smallest to largest is:
<Y=39°, <W=51°, <X=90°
The opposite sides to these angles must be ordered in the same way:
Opposite side to <Y: WX
Opposite side to <W: XY
Opposite side to <X: YW
Then the order of the sides from smallest to largest is:
WX, XY, YW
Answer:
No solution
Step-by-step explanation:
We have

For the sum it is not correct to assume

Note that for

it is assumed
and in your case
for 
In fact, considering a set
we have
that satisfy 
This means that, by definition 
Therefore,

because the sum is empty.
For

we have other problems. Actually, this case is really bad.
Note that
has no value. In fact, if we consider for the case
, the cosine function oscillates between
, and therefore it is undefined. Thus, we cannot evaluate

and then

has no solution
1/5 and 3/5
Hope this helps!