Just this question I've tried but don't understand it

Hdc produces microcomputer hard drives at four different production facilities (f1, f2, f3, and f4) hard drive production at f1,

OLEGan [10]

Let $D$ denote the event that an HD is defective, and $F_i$ the event that a particular HD was produced at facility $i$ .

You are asked to compute

$\mathbb P(F_2\mid D)$
$\mathbb P(F_4\mid D)$
$\mathbb P(D^C)$

From the definition of conditional probabilities, the first two will require that you first find $\mathbb P(D)$ . Once you have this, part (c) is trivial.

I'll demonstrate the computation for part (a). Part (b) is nearly identical.

(a)
$\mathbb P(F_2\mid D)=\dfrac{\mathbb P(F_2\cap D)}{\mathbb P(D)}$

Presumably, the facility responsible for producing a given HD is independent of whether the HD is defective or not, so $\mathbb P(F_2\cap D)=\mathbb P(F_2)\mathbb P(D)=0.20\times0.015$ .

Use the law of total probability to determine the value of the denominator:

$\mathbb P(D)=\mathbb P(D\mid F_1)+\mathbb P(D\mid F_2)+\mathbb P(D\mid F_3)+\mathbb P(D\mid F_4)$

We know each of the component probabilities because they are given explicitly: 0.015, 0.02, 0.01, and 0.03, respectively. So

$\mathbb P(D)=0.015+0.02+0.01+0.03=0.075$

and thus

$\mathbb P(F_2\mid D)=\dfrac{0.2\times0.015}{0.075}=0.04$

(b) Similarly,
$\mathbb P(F_4\mid D)=\dfrac{0.4\times0.03}{0.075}=0.16$

(c)
$\mathbb P(D^C)=1-\mathbb P(D)=0.925$

6 0

4 years ago

CPM homework 8.1.2 problem 8-19

Kisachek [45]

The area of the figure is 45 sq.mi and the perimeter is 23.5354 mi.

Area is the space occupied by a two dimensional object,

The area and perimeter of the given shape can be determined by dividing it into basic shapes.

The area and the perimeter of the shape given = Area of the rectangle +Area of upper triangle - Area of two small triangles at the bottom

Area of rectangle = 5 mi * 9 mi = 45 sq.mi

Area of upper Triangle = (1/2) *9*3 = 27/2 sq.mi

Area of small Triangle = (1/2) * 3*6 = 9 sq.mi

Area of other small Triangle = (1/2)*3*3 = 9/2 sq.mi

Area of the figure = 45 +13.5 -9-4.5

Area of the figure = 45 sq.mi

Similarly for Perimeter = Perimeter of the rectangle +Perimeter of upper triangle -Perimeter of two small triangles at the bottom

Perimeter = 28 -(3+6+6.708) -(3+3+4.2426) +(3+9+9.486

Perimeter = 23.5354 mi

Therefore , The area of the figure is 45 sq.mi and the perimeter is 23.5354 mi.

To know more about Area

brainly.com/question/27683633

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5 0

2 years ago

Use conversion factors to convert . Write the factor you used . 5 quarts to cups

34kurt

A quart is 4 cups. 5(4)=20 cups in a pint

I hope I helped :)

4 0

3 years ago

Find the value of p(1) if p(x) = (2x-5)(x-1) *

LuckyWell [14K]

The answer is 0 because if you substitute x with 1 and solve the equation you get 0

3 0

3 years ago

I need help. I will give brainliest and 99 points

sammy [17]

<span>The triangles are similar because they both have the same same angles.
Why? Because the two triangles are both right triangles and they both have another angle that is the same (as indicated by the circle fragment on the picture). That means that the last angle will be the same. Triangles are similar when they have the same angles but don't have to have the same lengths.

If the triangles are similar, the side lengths are in ratios. You are given the length of the side that corresponds with the third angle, which are 4 and 15. So the ratio of the lengths of the small to large triangle is 4:15. You are given another length (Height of Annie's eyes), which is 5. This can help you find the height of the house.

Let x=height of the house.
So 4/15 = 5/x
4x=5*15=75
x=75/4
x=18.75 ft

Hope this helps!</span><span>
</span>

8 0

3 years ago

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