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Ivenika [448]
3 years ago
9

The width of a vegetable garden is

Mathematics
2 answers:
sukhopar [10]3 years ago
3 0

Answer: So, the length (L) = 7 3/4 ft = 31/4 (as an improper fraction)

 

the width (W)  = (1/3)xL

 

So the width = 1/3 x (31/4) =

31/12 = 2  7/12 feet

Step-by-step explanation:

luda_lava [24]3 years ago
3 0
So you put ax3/4 and answer is ax3/4=3:4xa
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2) A = 678.5226, C = 92.316

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Step-by-step explanation:

1)

A = \Pi (\frac{D}{2})^2 = 3.14 * (\frac{26.4}{2})^2 = 3.14 * 13.2^2 = 547.1136

C = \Pi D = 3.14 * 26.4 = 82.896

2)

A = \Pi r^2 = 3.14*(14.7)^2 = 678.5226

C = 2\Pi r = 14.7*2 * 3.14 = 92.316

3)

A = \Pi (\frac{D}{2})^2 = 3.14 * (\frac{32.8}{2})^2 = 3.14 * 16.4^2 = 844.5344

C = \Pi D = 3.14 * 32.8 = 102.992

4)

A = \Pi (\frac{D}{2})^2 =  3.14 * (\frac{44.5}{2})^2 = 3.14 * 22.25^2 = 1554.49625

C = \Pi D = 44.5*3.14 = 139.73

5)

A = \Pi r^2 = 3.14*22.3^2 = 1561.4906

C = 2\Pi r = 2 * 3.14 * 22.3 = 140.044

6)

A = \Pi r^2 = 3.14 * 17.8^2 = 994.8776

C = 2\Pi r = 2 * 3.14 * 17.8 = 111.784

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