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zysi [14]
3 years ago
15

A triangle is considered equilateral has

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
6 0
Equilateral triangle means : a triangle with all 3 sides = in length
oee [108]3 years ago
5 0
3 equal sides and 3 equal angles
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6300 and 530 the value of 3 in 6300
Greeley [361]
The value of three is three hundred or 300 or 3 x 100
4 0
3 years ago
What is the probability of rolling a 1 or 2 when a six-sided die is rolled 700 times. Round your answer to the nearest whole num
Maurinko [17]

Answer: B. 233 (rounded)

Step-by-step explanation:

1: 700/6= 166.6

2: 166.6+166.6=233.332

3 round to 233

6 0
3 years ago
Read 2 more answers
Are f and g inverses of each other? Support your response algebraically
NeTakaya

Answer:

see explanation

Step-by-step explanation:

If f(x) and g(x) are the inverses of each other, then

f(g(x)) = g(f(x)) = x

f(g(x)) = f(x - \frac{1}{2}) = x - \frac{1}{2} + \frac{1}{2} = x

g(f(x)) = g(x + \frac{1}{2}) = x + \frac{1}{2} - \frac{1}{2} = x

Hence f(x) and g(x) are the inverse of each other


4 0
3 years ago
What is the perimeter of the polygon?
mr_godi [17]
Welp. I sure hope you like the Pythagorean theorem...
Top line:
One point is (-2,-2) while the other is (3,-3)
Thus the distance in between is sqrt((3-(-2))^2+(-3-(-2))^2)=sqrt(5^2+(-1)^2)=sqrt(26)
Most right line:
One point is (4,-6) while the other is (3,-3)
Thus the distance in between is sqrt((3-4)^2+(-3-(-6))^2)=sqrt((-1)^2+3^2)=sqrt(10)
Most bottom line:
One point is (1,-6) while the other is (4,-6)
Thus the distance in between is sqrt(4-1)^2+(-6-(-6))^2)=sqrt(3^2+0^2)=sqrt(9)=3
Most bottom left line:
One point is (1,-6) while the other is (-2,-4)
Thus the distance in between is sqrt((1-(-2))^2+(-6-(-4))^2)=sqrt(3^2+(-2)^2)=sqrt(13)
Lastly the most left line:
One point is (-2,-2) while the other is (-2,-4)
Thus the distance in between is sqrt((-2-(-2))^2+(-2-(-4))^2)=sqrt(0^2+(2)^2)=sqrt(4)=2
Thus to find the perimeter, we add up all the sides to get
sqrt(26)+sqrt(10)+3+sqrt(13)+2=16.8668 or B




6 0
3 years ago
Second derivative of sec^2(πx)
Digiron [165]
 <span>let y = sec^2 ( pi x ) 

y' = 2 sec ( pi x ) sec( pi x ) tan ( pi x ) pi 

y' = 2pi sec^2 ( pi x ) tan ( pi x ) 

y''= 2pi sec^2 ( pi x ) * sec^2 ( pi x ) * pi + 2pi tan ( pi x ) * 2pi sec^2 ( pi x ) tan ( pi x ) 

y'' = 2 pi^2 sec^4 ( pi x ) + 4 pi^2 sec^2 ( pi x ) tan^2 ( pi x )</span>
6 0
3 years ago
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