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vfiekz [6]
2 years ago
9

What is a true statement about negative exponents?

Mathematics
1 answer:
Nadya [2.5K]2 years ago
3 0

Answer:

Raising something to a negative exponent is just taking the reciprocal of the amount.

Step-by-step explanation:

Let's assume that you wanted to know what x^{-2} is.

To find it, you would take the reciprocal of the x amount. So x^{-2} becomes \frac{1}{x^{2}}.

This works because of the nature of exponents. Exponents represent the number of times you are multiplying a value by itself. So a^{3} would be equal to a · a · a. To increase the exponent, you increase the number of times the value is multiplied by itself: To increase a^{3} to a^{5}, you would have to multiply a with a^{3} two more times (a · a · a · a · a). To decrease the exponent, you must divide the value by itself. So to decrease a^{5} to a^{2}, you would have to divide a^{5} by a 3 times.

If the exponent is 0, the value is equal to 1. But you can still decrease the exponent into negative numbers. You just divide 1 by a the desired amount of times: \frac{1}{a^{3}} means that you are dividing 1 by a 3 times.

Hope this helps.

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Step-by-step explanation:

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5 0
2 years ago
There were 18 students running in a race. How many different arrangements of first, second, and third place are possible?
swat32

Answer:

There are 18 choices for first place, 17 for second, and 16 for third.

Therefore, there are 18 x 17 x 16=4896

So there are 4,896 ways possible

Step-by-step explanation:

Hope this helps:)...if not then sorry for wasting your time and may God bless you:)

8 0
2 years ago
Find the inverse for the relationship (1,-3 ), (-2, 3), (5, 1), (6, 4)
Tatiana [17]

Answer:

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Step-by-step explanation:

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8 0
2 years ago
The probability that a student is accepted to a prestigious college is 0.3. If 5 students from the same school apply, what is th
hodyreva [135]

Answer:0.849185

Step-by-step explanation:

Binomial probability formula we will use:

$P(x)=\frac{n !}{x !(n-x) !} p^{x} q^{n-x}$

where,

n=5$\\$\mathrm{P}$ (probability of success) $=0.3$\\q=1-p

The computation of the probability will be :

$P(x \leq 2 ; 5,0.3)=P(x=0 ; 5,0.3)+P(x=1 ; 5,0.3)+P(x=2 ; 5,0.3)+P(x=3 ; 5,0.3)$\\$=\left[\frac{5 !}{5 !(5-0) !}(0.3)^{0}(1-0.3)^{5-0}\right]+\left[\frac{5 !}{5 !(5-1) !}(0.3)^{1}(1-0.3)^{5-1}\right]$$+\left[\frac{5 !}{5 !(5-2) !}(0.3)^{2}(1-0.3)^{5-2}\right]$$++\left[\frac{5 !}{5 !(5-3) !}(0.3)^{3}(1-0.3)^{5-3}\right]$$++\left[\frac{5 !}{5 !(5-4) !}(0.3)^{4}(1-0.3)^{5-4}\right]$\\$=0.1681+0.3601+0.3087+0.006615+0.00567$\\$\Rightarrow 0.849185$

The probability that at most 4 are accepted = 0.849185

6 0
3 years ago
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