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vfiekz [6]
3 years ago
9

What is a true statement about negative exponents?

Mathematics
1 answer:
Nadya [2.5K]3 years ago
3 0

Answer:

Raising something to a negative exponent is just taking the reciprocal of the amount.

Step-by-step explanation:

Let's assume that you wanted to know what x^{-2} is.

To find it, you would take the reciprocal of the x amount. So x^{-2} becomes \frac{1}{x^{2}}.

This works because of the nature of exponents. Exponents represent the number of times you are multiplying a value by itself. So a^{3} would be equal to a · a · a. To increase the exponent, you increase the number of times the value is multiplied by itself: To increase a^{3} to a^{5}, you would have to multiply a with a^{3} two more times (a · a · a · a · a). To decrease the exponent, you must divide the value by itself. So to decrease a^{5} to a^{2}, you would have to divide a^{5} by a 3 times.

If the exponent is 0, the value is equal to 1. But you can still decrease the exponent into negative numbers. You just divide 1 by a the desired amount of times: \frac{1}{a^{3}} means that you are dividing 1 by a 3 times.

Hope this helps.

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Black_prince [1.1K]
4/11 * 10/8
= 1/11 * 10/2
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answer 5/11
you got it correct
7 0
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Solve trigonometric function<br><br> cos2∅ + sin∅ × csc∅ / sin2∅
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Answer:

Step-by-step explanation:

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\text {\sf \Large Solution :}

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3 0
2 years ago
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Help with matrices please? Any wrong/not applicable answers will be reported and BLOCKED
marin [14]

m x H = \left[\begin{array}{ccc}-25&37.5&-12.5\\\9\end{array}\right]

Step-by-step explanation:

Step 1; Multiply 5 with this matrix  \left[\begin{array}{ccc}-1&2\\4&8\\\end{array}\right] and we get a matrix \left[\begin{array}{ccc}-5&10\\20&40\\\end{array}\right]

Multiply the fraction  \frac{2}{5} with the matrix  \left[\begin{array}{ccc}-1&2\\4&8\\\end{array}\right] and we get \left[\begin{array}{ccc}-\frac{2m}{5} &\frac{4m}{5} \\\frac{8m}{5} &\frac{16m}{5} \\\end{array}\right]

Step2; Now equate corresponding values of the matrices with each other.

-5 = \frac{-2m}{5} and so on. By equating we get the value of m as \frac{25}{2}

Step 3; Add the matrices to get the value of matrix m.

Adding the three matrices on the RHS we get  \left[\begin{array}{ccc}2&9&-9\\\end{array}\right].

Step 4; Adding the matrices on the LHS we get the resulting matrix as H +

\left[\begin{array}{ccc}4&6&-8\\\9\end{array}\right]. Equating the matrices from step 3 and 4 we get the value of H as \left[\begin{array}{ccc}-2&3&-1\\\9\end{array}\right]

Step 5; Now to find the value of m x H we need to multiply the value of \frac{25}{2} with the matrix \left[\begin{array}{ccc}-2&3&-1\\\9\end{array}\right]

Step 6; Multiplying we get the matrix m x H = [ -25  \frac{75}{2}  \frac{-25}{2} ]

8 0
3 years ago
a man is standing on top of a cliff, 80 high, the angle of depression to a boat is 60° . calculate the distance of the boat from
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
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What does the 7-5 mean at the end?
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