Answer:
Option (G)
Step-by-step explanation:
Volume of the real cane = 96 in³
Volume of the model of a can = 12 in³
Volume scale factor = 
= 
Scale factor of the model = ![\sqrt[3]{\text{Volume scale factor}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Ctext%7BVolume%20scale%20factor%7D%7D)
![=\sqrt[3]{\frac{1}{8}}](https://tex.z-dn.net/?f=%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B8%7D%7D)
Therefore, scale factor of the model of a can = 
≈ 1 : 2
Option (G) will be the correct option.
<span><span>10: 2, 5 </span><span>90: 23, 35 </span><span>GCF: 2 5</span></span>
The answer is
(4x^3 - 5y^2) (16x^6 + 20x^3 y^2 +25y^4)
Answer:
p = 1.5 and q = 9
Step-by-step explanation:
Expand the right side then compare the coefficients of like terms on both sides, that is
4(x + p)² - q ← expand (x + p)² using FOIL
= 4(x² + 2px + p²) - q ← distribute parenthesis
= 4x² + 8px + 4p² - q
Comparing coefficients of like terms on both sides
8p = 12 ( coefficients of x- terms ) ← divide both sides by 8
p = 1.5
4p² - q = 0 ( constant terms ), that is
4(1.5)² - q = 0
9 - q = 0 ( subtract 9 from both sides )
- q = - 9 ( multiply both sides by - 1 )
q = 9
250 × 3 = 750
D. 750
And i think i have already answered this one before..
