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Furkat [3]
3 years ago
8

Which of these is always the largest?

Mathematics
2 answers:
Nadusha1986 [10]3 years ago
8 0

Answer:

Step-by-step explanation:

B

Vladimir79 [104]3 years ago
4 0

Answer:

obtuse angle

Step-by-step explanation:

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HALP PLEASE
Sergeeva-Olga [200]

Answer:

A: -2

Step-by-step explanation:

Hopefully this helps!

5 0
3 years ago
How far does the barnacle travel in one revolution of the water wheel?<br><br> m
nasty-shy [4]

Answer:

2pi

Step-by-step explanation:

Right on edg assignment

8 0
3 years ago
Read 2 more answers
Solve for m.<br> 22m^2 + 7m - 2 = 0
pshichka [43]

Answer:

x= -1/2 and x=2/11

Step-by-step explanation:

Write the 7x as a difference. It'll make it easier to factor out. An example of this would be 11x-4x

Therefore, the equation would look like this: 22x^2 + 11x-4x -2 =0

Look at it as if there are two equations: 22x^2+11x and -4x-2

Factor out the greatest common factor, which is 11 from the first equation. The equation will then look like this: 11x(2x+1)

Take the GCF for the second equation as well (which is -2). The equation should then also look like this: (2x+1)

Use the numbers on the outside of each of the parenthesis to form its own equation (to factor it out). This will be 11x-2

Now we have factored! Since the parenthesis equations are the same, we know that that is also part of the equation, so:

(11x-2)(2x+1)

Solve each equation for x by equaling them both to zero

5 0
3 years ago
Here is the questions sorry
xxMikexx [17]

Answer:

I think the answer is about 10

Step-by-step explanation:

6 0
4 years ago
If a snowball melts so that its surface area decreases at a rate of 3 cm2/min, find the rate (in cm/min) at which the diameter d
grin007 [14]

Answer:

The diameter decreases at a rate of 0.053 cm/min.

Step-by-step explanation:

Surface area of an snowball

The surface area of an snowball has the following equation:

S_{a} = \pi d^2

In which d is the diameter.

Implicit differentiation:

To solve this question, we differentiate the equation for the surface area implictly, in function of t. So

\frac{dS_{a}}{dt} = 2d\pi\frac{dd}{dt}

Surface area decreases at a rate of 3 cm2/min

This means that \frac{dS_{a}}{dt} = -3

Tind the rate (in cm/min) at which the diameter decreases when the diameter is 9 cm.

This is \frac{dd}{dt} when d = 9. So

\frac{dS_{a}}{dt} = 2d\pi\frac{dd}{dt}

-3 = 2*9\pi\frac{dd}{dt}

\frac{dd}{dt} = -\frac{3}{18\pi}

\frac{dd}{dt} = -0.053

The diameter decreases at a rate of 0.053 cm/min.

7 0
3 years ago
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