Answer:
22 inches
Step-by-step explanation:
The perimeter of a trapezoid is the sum of the lengths of its four sides. If one or more of the lengths is not known, you can sometimes use the Pythagorean Theorem to find it.
We draw the shape of trapezoid all have 6 sides
Two faces are trapezoids and four faces are rectangles
length = 3 inches
height = 5 inches
top side = x
bottom side = 2x (twice the size of top)
To find the perimeter, add the lengths of all four sides.
P=5+5+2x+x =3x + 10 units When we come back to this.
Finding x
if 3 is the midpoint length
We use 1/2
NB/ To undo multiplication 1/2 after we find the perimeter we can divide by half.
So this works together
We take p = H + 5
-5 = H
We plug in for area 3 x 5 = 15 + 15 = 30
So The top line = 4
The bottom x 2 = 8
As 30-5 = 25 we find 25
We add 4, 8, 5 + 5 and find 22 is the answer.
Now divide 22 - 5 by 1/2 half of 17 = 8.5
8 and half.
We have top 4, and 8 bottom.
Answer:
Equation C: 5/8x + 2..5 = 3/8x + 1.5 + 1/4x
Step-by-step explanation:
Let us go through each of the equations one by one.
Equation A:
This simplifies to
which has infinitely many solutions.
Equation B:
this simplifies to
which is exactly one solution.
Equation C:
this simplifies to
There's no way this is going to be possible; this equation has no solutions.
Equation D:
this gives
which is exactly one solution.
Thus we see that it is equation C that has no solutions.
To best emphasize the number of defects. Manager should use graph 3 (refer the image shown):
If we talk about graph 1, it can also be used but usually we put the time line on the horizontal axis, for the convenience and the quantity to be measured on the y-axis. In the graph 1, the time is placed on the vertical axis (x-axis) so it would not be a good pick for the manager.
Same is the case with graph 2 again we have time on the vertical axis. So it is not a good idea to with graph 2.
Graph 3 could be the best to emphasize the number of defects because first of all time is placed on the horizontal axis and the quantity to be shown is on the vertical axis. Secondly, the range of the vertical axis is less so it is easy to observe the data set on the graph quite distinctively. Therefore, graph 3 is the best pick.
Graph 4 is placed correctly in terms of vertical and horizontal axes but the range of vertical axis is quite high due to which the dispersion or the display of the data is quite compressed and it gets hard to visualize.
