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lukranit [14]
3 years ago
15

Thee population of a town, P(t), is 2000 in the year 2010. Every year, it increases by 1.5%. Write an equation for the populatio

n of this town t years from 2010.
I clicked that by accident so i’m not sure if it’s correct.

Mathematics
1 answer:
steposvetlana [31]3 years ago
7 0

Given:

In 2010, the population of a town = 2000

Every year, it increase by 1.5%

To find the equation P(t) which represents the population of this town t years from 2010.

Formula

If a be the original population of a town and it increases by b% every year, after t year the population will be

a (1+\frac{b}{100} )^{t}

Now,

Taking, a  =2000, b = 1.5 we get,

P(t) = 2000(1+\frac{1.5}{100} )^{t}

or, P(t) = 2000(1+0.015)^{t}

Hence,

The population of this town t years from 2010 P(t) = 2000(1+0.015)^{t}, Option D.

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2/3 yard= 1 pillow

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elixir [45]
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6 0
2 years ago
What are the solutions of the equation x^4 + 6x^2 + 5 = 0? Use u substitution to solve.
Radda [10]

Answer:

second option

Step-by-step explanation:

Given

x^{4} + 6x² + 5 = 0

let u = x², then

u² + 6u + 5 = 0 ← in standard form

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Equate each factor to zero and solve for u

u + 1 = 0 ⇒ u = - 1

u + 5 = 0 ⇒ u = - 5

Change u back into terms of x, that is

x² = - 1 ( take the square root of both sides )

x = ± \sqrt{-1} = ± i ( noting that \sqrt{-1} = i ), and

x² = - 5 ( take the square root of both sides )

x = ± \sqrt{-5} = ± \sqrt{5(-1)} = ± \sqrt{5} × \sqrt{-1} = ± i\sqrt{5}

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