Question

A volleyball team had 6 boys and 5 girls on it. The team needed 2 equipment managers. The coach selected 1 player at random to be an equipment manager and then selected 1 of the remaining players at random to be the other equipment manager.
What is the probability that both equipment managers were girls? Express your answer in simplest form.

Answer 1

Proability first equipment manager is a girl: $\frac{5}{11}$
Probability second equipment manager is a girl: $\frac{4}{10}$

Probability both events occured = $\frac{5}{11}$ x $\frac{4}{10}$
= $\frac{2}{11}$

Answer 2

There is a 25%chance because there is four possible outcomes