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2 years ago

Guys someone shared their notes with me how should I thank them

Chemistry

2 answers:

Rzqust [24]2 years ago

8 0

by answering thiers questions also then be kind to share

Dvinal [7]2 years ago

6 0

مسويها اصريت تصريحات

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3 years ago

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What happens in a subduction zone?

Soloha48 [4]

It’s been awhile but I think it is c

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3 years ago

How does rock candy relate to the igneous rock formation?

sveta [45]

Answer:

The candy is heated then cooled, turning solid like a igneous rock.

Explanation:

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3 years ago

When you apply 1000 joules of energy to 50 grams of water its temperature changes to 30 degrees . What was the initial temperatu

expeople1 [14]

Answer:

25.2°C

Explanation:

Given parameters:

Energy applied to the water = 1000J

Mass of water = 50g

Final temperature = 30°C

Unknown:

Initial temperature = ?

Solution:

To solve this problem, we use the expression below:

H = m c Ф

H is the energy absorbed

m is the mass

c is the specific heat capacity

Ф is the change in temperature

1000 = 50 x 4.184 x (30 - initial temperature )

1000 = 209.2(30 - initial temperature)

4.78 = 30 - initial temperature

4.78 - 30 = - initial temperature

Initial temperature = 25.2°C

7 0

3 years ago

If 125 ml of o2 gas exerts a pressure of 1.0 atm inside a cylinder, what will the pressure be if the cylinder compressed the vol

Lelu [443]

<h2>Hello!</h2>

The answer is: The new pressure is 1.67 atm.

From the statement, we know that the temperature remains constant and the gas volume is changing, meaning that the new pressure will be different than the first pressure.

Since the temperature remains constant, we can calculate the new pressure using the Boyle's Law.

The Boyle's Law states that:

$P_{1}V_{1}=P_{2}V_{2}$

Where,

P is the pressure of the gas.

V is the volume of the gas.

Then, the given information is:

$V_{1}=125ml=0.125L\\P_{1}=1atm\\V_{2}=75ml=0.075L$

Remember, 1 L is equal to 1000 mL.

So,

$125mL*\frac{1L}{1000mL}=\frac{125mL*1L}{1000mL}=0.125L\\\\75mL*\frac{1L}{1000mL}=\frac{75mL*1L}{1000mL}=0.075L$

So, calculating the new volume, we have:

$P_{1}V_{1}=P_{2}V_{2}\\\\1atm*0.125L=P_{2}*0.075L\\\\P_{2}=\frac{1atm*0.125L}{0.075l}=1.67atm$

Hence, the new pressure is 1.67 atm.

Have a nice day!

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3 years ago