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Charra [1.4K]
4 years ago
13

This is no help Ok so bydhcvx

Chemistry
2 answers:
Elodia [21]4 years ago
6 0
Do you need help with something?
dedylja [7]4 years ago
5 0

Answer:ok

Explanation: 38732873457438573455101010101010010101010101010101010101010101010101010101010101010101010101010101010101101010101

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Which distinguishes an atom of one element from an atoms of a different element?<br> Please help
yaroslaw [1]

Answer:

because the number of electrons and protons differs

3 0
3 years ago
Read 2 more answers
Which of the following Group 17 elements is the least reactive?
satela [25.4K]

The given question is incomplete. The complete question is :

Which of the following Group 17 elements is the least reactive

a) Flourine

b) Chlorine

c) Astatine

d) Iodine

Answer: c) Astatine

Explanation:

Halogen is the name given to Group 17 family with general electronic configuration of ns^2np^5 which have 7 valence electrons and thus easily gain one electron to attain stable configuration.

As we move down the group from flourine to chlorine to bromine to iodine to astatine , the valence shell moves farther from nucleus and thus tendency to accept the electron decreases and thus reactivity also decreases.

Thus Astatine is the least reactive of all.

7 0
3 years ago
The two gases, H2 and O2, were allowed to effuse under the same conditions through a pinhole. If the rate of effusion of O2 was
TEA [102]

The rate of effusion of H₂ : 7.2 x 10⁻² m/s

<h3>Further explanation  </h3>

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or  

the effusion rates of two gases = the square root of the inverse of their molar masses:  

\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }

or  

\rm M_1\times r_1^2=M_2\times r_2^2

MW₁ O₂ = 32 g/mol

MW₂ H₂ = 2 g/mol

\tt \dfrac{1.8\times 10^{-2}}{r_2}=\sqrt{\dfrac{2}{32} }\\\\\dfrac{(1.8\times 10^{-2})^2}{r_2^2}=\dfrac{2}{32}\\\\r_2=0.072=7.2\times 10^{-2}~m/s

7 0
3 years ago
What happens when you break earphones into smaller pieces
Vadim26 [7]

Answer:

Well its not gonna work anymore and you will be able to all the wires in the earphones!

Explanation:

6 0
4 years ago
Groundwater in Pherric, New Mexico, initially contains 1.800 mg/L of iron as Fe3+. What must the pH be raised to in order to pre
xenn [34]

Answer : The pH will be, 3.2

Explanation :

As we known that the value of solubility constant of ferric hydroxide at 25^oC is, 2.79\times 10^{-39}

Amount or solubility of iron consumed = (1.800 - 0.3) mg/L = 1.5 mg/L

The given solubility of iron convert from mg/L to mol/L.

1.5mg/L=\frac{1.5\times 10^{-3}g/L}{56g/mol}=2.7\times 10^{-7}mol/L

The chemical reaction will be:

Fe(OH)_3\rightarrow Fe^{3+}+3OH^-

The expression of solubility constant will be:

K_{sp}=[Fe^{3+}]\times [3OH^-]^3

Now put all the given values in this expression, we get the concentration of hydroxide ion.

2.79\times 10^{-39}=(2.7\times 10^{-7})\times [3OH^-]^3

[OH^-]=1.5\times 10^{-11}M

Now we have to calculate the pOH.

pOH=-\log [OH^-]

pOH=-\log (1.5\times 10^{-11})

pOH=10.8

Now we have to calculate the pH.

pH+pOH=14\\\\pH=14-pOH\\\\pH=14-10.8\\\\pH=3.2

Therefore, the pH will be, 3.2

4 0
4 years ago
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