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MrRa [10]
4 years ago
10

Somebody please help me

Mathematics
1 answer:
miss Akunina [59]4 years ago
4 0
I chose x^3, it would be a cubic function , then it’s -(x-6 )^3 -2
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Two trains begin in Milford and end in Pinkerton, which is 300 miles away. Train A leaves Milford at 10:00 a.M. And travels at a
cluponka [151]

Answer:

B. Train B  

Step-by-step explanation:

We are told that Milford and Pinkerton is 300 miles away.

Train A leaves Milford at 10:00 am. There are 3 hours between 10:00 am to 1:00 pm. So let us find distance traveled by train A in 3 hours.

\text{Distance}=\text{Speed*Time}  

\text{Distance traveled by train A}=90\frac{\text{ miles}}{\text{ hour}}\times 3\text{ hours}

\text{Distance traveled by train A}=90\times 3{\text{ miles}

\text{Distance traveled by train A}=270{\text{ miles}

Since train A will cover 270 miles in 3 hours and distance between Milford and Pinkerton is 300 miles, therefore, train A will not arrive Pinkerton before 1:00 pm.

Since there are 5 hours between 8:00 am to 1:00 pm, so let us find distance traveled by train B in 5 hours.

\text{Distance traveled by train B}=70\frac{\text{ miles}}{\text{ hour}}\times 5\text{ hours}

\text{Distance traveled by train B}=70\times 5 \text{ miles}

\text{Distance traveled by train B}=350\text{ miles}  

Since train B will cover 350 miles in 5 hours, therefore, train B will arrive Pinkerton before 1:00 pm and option B is the correct choice.

5 0
4 years ago
PLEASE HELP!!!!!!!!!!!!!!!!
lakkis [162]

Answer:

false i think? and true

Step-by-step explanation:


8 0
3 years ago
Convert 54,000,000,000 to scientific notation
kvasek [131]

Answer:

5.4 * 10^10

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
On a certain day, the temperature in Seattle was -5° and the temperature in Houston was 10°. How many degrees lower was the temp
yarga [219]

Answer:

15 degrees lower

Step-by-step explanation:

When you are trying to find the difference between a negative and positive number, add both numbers and you will get the difference. In this case it was 15.

Sorry, math isn't my strongest suit, but i hoped this helped!

8 0
3 years ago
Sebastian solved the radical equation y + 1 = but did not check his solution. (y + 1)2 = y2 + 2y + 1 = –2y – 3 y2 + 4y + 4 = 0 (
Softa [21]

Answer:

There are no true solutions to the equation.

Step-by-step explanation:

<u><em>The correct equation is</em></u>

y+1=\sqrt{-2y-3}

Solve for y

squared both sides

(y+1)^2=(-2y-3)

(y^2+2y+1)=(-2y-3)

y^2+2y+1+2y+3=0

y^2+4y+4=0

(y+2)(y+2)=0

y=-2

<em>Verify</em>

substitute the value of y in the original expression

-2+1=\sqrt{-2(-2)-3}

-1=1 ----> is not true

therefore

There are no true solutions to the equation.

4 0
3 years ago
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