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MrRa [10]
4 years ago
10

Somebody please help me

Mathematics
1 answer:
miss Akunina [59]4 years ago
4 0
I chose x^3, it would be a cubic function , then it’s -(x-6 )^3 -2
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What is the solution to the equation fraction 1 over 3x = 6?
finlep [7]
X = 18 for this one.............
6 0
3 years ago
Read 2 more answers
The expression represents the cost of Janelle’s cell phone bill, where m represents the number of minutes of use.0.05m + 12
Sergio039 [100]

<u>The question is </u>

What is the constant in the expression?

we know that

c=0.05m+12

where

c---------> the cost of Janelle’s cell phone bill

m-------> represents the number of minutes of use

0.05------->  represent the cost per minute (slope of the linear equation)

12 ------->  represent the constant in the expression

therefore

<u>the answer is</u>

The constant is 12


4 0
3 years ago
Read 2 more answers
-1/3x-4/3y=-2 1/3x-2/3y=4 using elimination
Minchanka [31]

-1/3x-4/3y=2

1/3x-2/3y=4

First realize that the coefficient of x is -1/3 and 1/3 which can be eliminated with addition

Adding the two equations together gets

-6/3y=6

Simplify

-2y=6

y=-3

Substitute back into original equation

1/3x-2/3(-3)=4

1/3x+2=4

1/3x=2

x=6

Answer

x=6, y=-3

Check answer

-1/3(6)-4/3(-3) =?= 2

                -2+4=2

                     2=2

Done!

5 0
3 years ago
An ellipse has a co-vertex at (–8, 9) and a foci at (4, 4). If the center of the ellipse is located below the given co-vertex, t
vovikov84 [41]

Answer:

Step-by-step explanation:

“the center of the ellipse is located below the given co-vertex”

Co-vertex and center are vertically aligned, so the ellipse is horizontal.

Equation for horizontal ellipse:

(x-h)²/a² + (y-k)²/b² = 1

with

a² ≥ b²

center (h,k)

vertices (h±a, k)

co-vertices (h, k±b)

foci (h±c,k), c² = a² -b²

One co-vertex is (-8,9), so h = -8.

One focus is (4,4), so k = 4.

Center (h,k) = (-8,4)

c = distance between center and focus = |-8 - 4| = 12

b = |9-k| = 5

a² = c² + b² = 169

(x+8)²/169 + (y-4)²/25 = 1

7 0
3 years ago
a total of 234 tickets were sold for the school play. they were either adult tickets or student tickets. the number of students
sweet-ann [11.9K]

Answer:

78 adult tickets were sold

2x + x = 234

3x = 234

x = 78

7 0
3 years ago
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