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2 years ago

Factor the polynomial expression 4x3 - 4.

Mathematics

1 answer:

Sloan [31]2 years ago

3 0

<h3>Answer: 4(x - 1)(x^2 + x + 1)</h3>

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Work Shown:

4x^3 - 4

4(x^3 - 1)

4(x - 1)(x^2 + x + 1)

In the last step, I used the difference of cubes factoring formula which is

a^3 - b^3 = (a - b)(a^2 + ab + b^2)

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Solve for u. 31.25 = u/5

ipn [44]

Answer:

u = 156.25

Step-by-step explanation:

Step 1: Write equation

31.25 = u/5

Step 2: Solve for <em>u</em>

Multiply both sides by 5: 156.25 = u
Rewrite: u = 156.25

Step 3: Check

<em>Plug in u to verify it's a solution.</em>

31.25 = 156.25/5

31.25 = 31.25

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2 years ago

Read 2 more answers

Find The Area of triangle ABC

Sergeeva-Olga [200]

Answer:

b. area = 18 square units

Step-by-step explanation:

area of a triangle = 1/2 * base * height

area = 1/2 (6+3) + (6-2)

area = 1/2 * 9 * 4

area = 18 square units

therefore the answer is b.

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2 years ago

In 2012 your car was worth $10,000. In 2014 your car was worth $8,850. Suppose the value of your car decreased at a constant rat

monitta

Answer:

The function to determine the value of your car (in dollars) in terms of the number of years t since 2012 is:

$f(t) = 10000(0.9407)^t$

Step-by-step explanation:

Value of the car:

Constant rate of change, so the value of the car in t years after 2012 is given by:

$f(t) = f(0)(1-r)^t$

In which f(0) is the initial value and r is the decay rate, as a decimal.

In 2012 your car was worth $10,000.

This means that $f(0) = 10000$ , thus:

$f(t) = 10000(1-r)^t$

2014 your car was worth $8,850.

2014 - 2012 = 2, so:

$f(2) = 8850$

We use this to find 1 - r.

$f(t) = 10000(1-r)^t$

$8850 = 10000(1-r)^2$

$(1-r)^2 = \frac{8850}{10000}$

$(1-r)^2 = 0.885$

$\sqrt{(1-r)^2} = \sqrt{0.885}$

$1 - r = 0.9407$

Thus

$f(t) = 10000(1-r)^t$

$f(t) = 10000(0.9407)^t$

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2 years ago

What is an algebraic expression for the following word phrase:

lesya [120]

Required algebraic expression is 8/(x - m)

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3 years ago

Pls help being timed

Sloan [31]

He needs 9 hours

hope this helps

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2 years ago