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emmainna [20.7K]

3 years ago

11

Simplify: |5.74 + 2.89| – |16.20 + 41.32|

1 answer:

Charra [1.4K]3 years ago

7 0

Answer:

-48.89

Step-by-step explanation:

|5.74 + 2.89| – |16.20 + 41.32

|8.63| – |57.52|

= - 48.89

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Raylan opened a savings account with $100. After 5 years there is $122. 50 in the account. What is his simple interest rate?

serious [3.7K]

<h3>Answer:</h3>

4.5% annually

<h3>Step-by-step explanation:</h3>

Simple interest is the amount of interest added to a singular sum of money at a fixed rate.

Formula

The formula for simple interest is A = P(1+rt). In this formula, A is the total amount of money in the account, P is the original amount deposited, r is the rate of interest as a decimal, and t is the time in years.

Calculations

To find the rate, plug the information we know into the formula above

122.50 = 100(1+r*5)

Divide both sides by 100

1.225 = 1 + r*5

Subtract 1 from both sides

0.225 = r*5

Divide both sides by 5

0.045 = r

This gives us the rate as a decimal. So, to find the rate as a percent. Do this by moving the decimal 2 places to the right (or just multiply by 100, they do the same thing). This means that the rate of simple interest is 4.5%.

5 0

2 years ago

Thx and have a great day!!

Elan Coil [88]

Answer:A

Step-by-step explanation:<3and <11 are corresponding angles, and corresponding angles are congruent

7 0

3 years ago

A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0

3 years ago

jill received 45 ballots from the student council election. Mr. Alvarez, the advisor drops off quite a few more and jill now has

Vitek1552 [10]

Answer: 205

Step-by-step explanation:

Initially, Jill received ballots from the student council election = 45

After, dropping ballot by Mr. Alvarez, new ballots he has = 250

Hence, The Ballots drooping by Mr. Alvarez = new ballots Jill has - Initial ballots Jill has

= 250 - 45

= 205

Therefore, Mr. Alvarez drop off 205 ballots.

8 0

3 years ago

Use synthetic substitution to evaluate the polynomial P(x) = x^3-3x^2+4x-7 for x=3

Zina [86]

Answer:

$\frac{x^3-3x^2+4x-7}{x-3} =(x^2+4)+\frac{5}{x-3}$

Step-by-step explanation:

We are given polynomial as

$P(x)=x^3-3x^2+4x-7$

and it is divided by x=3 or x-3

we can use synthetic division

so, we got

Remainder =5

Quotient is

$=x^2+0x+4$

$=x^2+4$

we can write as

$\frac{x^3-3x^2+4x-7}{x-3} =(x^2+4)+\frac{5}{x-3}$

3 0

3 years ago