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Kaylis [27]
3 years ago
14

What is the pH of a 2.5x 10^-6M Solution of HCI?​

Chemistry
1 answer:
Tomtit [17]3 years ago
5 0

Answer:

5.6

Explanation:

since HCl is a strong acid we know that it completely dissasociates into H+ and Cl-

We can just treat the HCl as the H+ concentration and take the -log

-log(2.5E-6) = 5.6

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Describe the porosity and permeability of Antarctic soil.
iren2701 [21]

Answer:

Explanation: Geography · College. +5 pts ... Answer. 1.9/5. 16. Girly1004. Ambitious. 1 answer. 4 people helped ... are places that show evidence of a massive ice sheet that existed around 250 million years ago.

8 0
3 years ago
During the combustion of 5.000 g of octane, C8H18, 239.5 kcal is released. Write a balanced equation for the combustion reaction
lidiya [134]

The chemical equation for this combustion reaction is:

<span>C8H18  +  O2  -->  CO2  +  H2O</span>

 

Balancing by adding whole number coefficients:

<span>2 C8H18  + 25 O2  -->  16 CO2  + 18 H2O</span>

 

Including the phases:

<span>2 C8H18 (l)  + 25 O2 (g)  -->  16 CO2 (g) + 18 H2O (l)</span>

<span>where g is gas and l is liquid</span>

3 0
3 years ago
A solution in which the [H+] is 1.0 × 10–4 mol/L is said to be
Arturiano [62]
The answer is acidic 
5 0
4 years ago
Which statement describes proper conduct in the laboratory?
Harrizon [31]

Answer:

D.

Explanation:

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6 0
3 years ago
Oxycodone (C18H21NO4), a narcotic analgesic, is a weak base with pKb = 5.47. Calculate the pH of a .00500 M oxycodone solution.
Ganezh [65]

Answer:

pH = 10.11

Explanation:

Hello there!

In this case, since it is possible to realize that this base is able to acquire one hydrogen atom from the water:

C_{18}H_{21}NO_4+H_2O\rightleftharpoons C_{18}H_{21}NO_4H^+OH^-

We can therefore set up the corresponding equilibrium expression:

Kb=\frac{[C_{18}H_{21}NO_4H^+][OH^-]}{[C_{18}H_{21}NO_4]}

Which can be written in terms of the reaction extent, x:

Kb=\frac{x^2}{0.00500M-x}=3.39x10^{-6}

Thus, by solving for x we obtain:

x_1=-0.000132M\\\\x_2=0.0001285M

However, since negative solutions are now allowed, we infer the correct x is 0.0001285 M; thus, the pOH can be computed:

pOH=-log(x)=-log(0.0001285)=3.89

And finally the pH:

pH=14-pOH=14-3.89\\\\pH=10.11

Best regards!

5 0
3 years ago
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