1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
victus00 [196]
3 years ago
7

A) which substances are the products? ______________________________

Chemistry
1 answer:
FromTheMoon [43]3 years ago
5 0
In a chemical reaction the products are found at the right of the equation, the products are what is being made once the reaction is complete. On the right side if the chemical equation is the reactants or starting materials, these are the substances that are combined to provide a product on the right side of the equation. Since I am not able to see the equation, just simple add all the carbons that are on the left and that will tell you how many carbons there are in total on the reactant side and if you add all of the carbons on the right side it will let you know how many carbons there are on the product side. The same steps can be taken for Oxygen.
I am unable to answer the last one as I need more information. But basically the law states that any system for which matter and energy cannot be transfer as it is a closed system, then since the system's mass can't change then it cannot be added or subtracted
You might be interested in
How many grams are there in 2.00 moles of copper (ii) oxide
tatuchka [14]

Answer: 159 grams

Explanation:

Copper (ii) oxide has the chemical formula CuO.

Now given that:

Mass of CuO in grams = ? (let unknown value be Z)

Number of moles = 2.00 moles

Molar mass of CuO = ?

For the molar mass of CuO: Atomic mass of Copper = 63.5g ; Oxygen = 16g

= 63.5g + 16g

= 79.5 g/mol

Apply the formula:

Number of molecules = (mass in grams/molar mass)

2.00 moles = (Z / 79.5 g/mol)

Z = 79.5 g/mol x 2.00 moles

Z = 159g

Thus, there are 159 grams in 2.00 moles of copper (ii) oxide

7 0
3 years ago
Enough of a monoprotic weak acid is dissolved in water to produce a 0.0118 M solution. The pH of the resulting solution is 2.32
ser-zykov [4K]

Answer:

1.94 × 10⁻³

Explanation:

Step 1: Calculate the concentration of H⁺ ions

We will use the definition of pH.

pH = -log [H⁺]

[H⁺] = antilog -pH = antilog -2.32 = 4.79 × 10⁻³ M

Step 2: Calculate the acid dissociation constant (Ka) of the acid

For a monoprotic weak acid, whose concentration (Ca) is 0.0118 M, we can use the following expression.

Ka = [H⁺]²/Ca

Ka = (4.79 × 10⁻³)²/0.0118 = 1.94 × 10⁻³

4 0
3 years ago
What is the first answer ?
QveST [7]

Answer:

d....

Explanation:

yes its d

sorry

7 0
3 years ago
Concentrations-
GaryK [48]
Final molarity is 0.607M

Work shown on photo:

3 0
3 years ago
Water cannot dissolve all substances that are made from ionic bonds. This is probably because
Step2247 [10]
B, some ionic bonds are too strong for the attractions of water molecules to pull them apart
6 0
3 years ago
Other questions:
  • How is chemical and physical properties of matter like in different
    15·1 answer
  • Which statements are true? The oxidation number for Cu(s) is +2. An oxidizing agent gains electrons. Na+ is formed from the redu
    10·2 answers
  • 29 Positrons and beta particles have(1) the same charge and the same mass
    11·1 answer
  • Idk how to do this at all!!!
    8·1 answer
  • AlCl3 + Na NaCl + Al Did Cl change oxidation number?
    11·2 answers
  • _______________ is when a compound containing carbon and hydrogen (and sometimes oxygen) combines with oxygen gas to produce car
    12·1 answer
  • What is the atomic number of an oxygen atom with 8 protons and 10 neutrons in the nucleus.
    14·1 answer
  • Find ΔHrxn for the following reaction: <br><br> 2PbS(s)+3O2(g)→2PbO(s)+2SO2(g)
    11·1 answer
  • If we wanted to add to the Venn diagram to reflect the Arrhenius acid-base theory, which statements would be MOST appropriate? A
    14·1 answer
  • Which gas law is represented by the following equation: P1/T1 = P2/T2
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!