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victus00 [196]
3 years ago
7

A) which substances are the products? ______________________________

Chemistry
1 answer:
FromTheMoon [43]3 years ago
5 0
In a chemical reaction the products are found at the right of the equation, the products are what is being made once the reaction is complete. On the right side if the chemical equation is the reactants or starting materials, these are the substances that are combined to provide a product on the right side of the equation. Since I am not able to see the equation, just simple add all the carbons that are on the left and that will tell you how many carbons there are in total on the reactant side and if you add all of the carbons on the right side it will let you know how many carbons there are on the product side. The same steps can be taken for Oxygen.
I am unable to answer the last one as I need more information. But basically the law states that any system for which matter and energy cannot be transfer as it is a closed system, then since the system's mass can't change then it cannot be added or subtracted
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Please help with the attached picture question 21, 22, 23
klasskru [66]

Explanation:

21. The given molecule for cracking is tetradecane.

On cracking it forms one mole of decane (C10H22) and two moles of ethene gas.

The chemical equation is shown below:

C_1_4H_3_0->C_1_0H_2_2+2C_2H_4

22. The essential condition for the formation of an ester is the reaction of alcohol and acid in presence of concentrated sulfuric acid.

Thus among the given options, the first option is the correct one.

23. Isomers of butanol are shown below:

It is 2-butanol.

The position of -OH group changes to the second carbon.

5 0
3 years ago
Which of the following are examples of physical properties of ethanol? Select all that apply.
bazaltina [42]
Ethanol is: flammable, liquid at room temperature, the boiling point is 78.37 ° C.
7 0
3 years ago
1.2 kg of aluminum at 20oC is added to 1.5 kg of water at 80oC. After the system reaches thermal equilibrium, what is its final
Lubov Fominskaja [6]

Answer:

The final temperature is 71.19 °C

Explanation:

Step 1: Data given

Mass of aluminium = 1.2 kg = 1200 grams

Temperature of aluminium = 20.0 °C

Specific heat of aluminium = 0.900 J/g°C

Mass of water = 1.5 kg = 1500 grams

Temperature of water = 80.0 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate the final temperature

heat gained = heat lost

Q(aluminium) = - Q(water)

Q = m*c*ΔT

m(aluminium) * c(aluminium) * ΔT(aluminium) = - m(water) * c(water) * ΔT(water)

⇒ with mass of aluminium = 1200 grams

⇒ with specific heat of aluminium = 0.900 J/g°C

⇒ with ΔT = The change in temperature = T2 - T1 = T2 - 20.0 °C

⇒ with mass of water = 1500 grams

⇒ with specific heat of water = 4.184 J/g°C

⇒ with ΔT = The change in temperature = T2 - T1 = T2 - 80.0°C

1200 * 0.900 * (T2-20.0°C) = -1500 * 4.184 * (T2 - 80.0°C)

1080 * (T2 - 20.0°C) = -6276 * (T2 - 80.0°C)

1080 T2 - 21600 = -6276T2 + 502080

7356T2 = 523680

T2 = 71.19 °C

The final temperature is 71.19 °C

8 0
3 years ago
Give the percent yield when 28.16 g of CO2 are formed from the reaction of 8.000 moles of C8H18 with 16.00 moles of O2.
kipiarov [429]

Answer:

Percent yield of CO₂ is 6.25 %.

Explanation:

Given data:

Percent yield of CO₂ = ?

Actual yield of CO₂ = 28.16 g

Number of moles of C₈H₁₈ = 8.000 mol

Number of moles of O₂ = 16.00 mol

Solution:

Chemical equation:

2C₈H₁₈ + 25O₂  →  16CO₂ + 18H₂O

Now we will compare the moles of C₈H₁₈ and O₂  with CO₂.

                 C₈H₁₈            :          CO₂

                    2                :             16

                  8.000          :            16/2×8.000 = 64 mol

                   O₂               :             CO₂

                    25              :              16

                     16              :              16/25×16= 10.24 mol

Less number of moles  of CO₂ are produced from 16 moles of O₂. it will limit the yield of CO₂.

Grams of CO₂ produced:

Mass = number of moles × molar mass

Mass = 10.24 mol  × 44 g/mol

Mass = 450.56 g

Percentage yield of CO₂:

Percentage yield = actual yield / theoretical yield × 100

Percentage yield = 28.16 g/ 450.56 g× 100

Percentage yield = 6.25 %

               

   

7 0
3 years ago
What is the formula of the compound Pentasilicon trioxide ?
zvonat [6]

Answer: the molecular formula of  trioxide is ClOClO3 or Cl2O4

hope its helps you.

keep smiling be happy stay safe

5 0
3 years ago
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