Answer:
[H⁺] = 5.754 x 10^-13 M
Explanation:
Since pH is the negative log of the hydronium concentration, we can solve for hydronium concentration and then plug in our given pH:
pH = -log[H⁺]
-pH = log[H⁺]
10^-pH = [H⁺]
Let's plug in our pH:
[H⁺] = 10^-pH = 10^-12.24 = 5.754 x 10^-13 M
Answer:
431.38 mg protein / mL
Explanation:
This is an example of the <em>Kjeldahl method</em>, for nitrogen determination. All nitrogen atoms in the protein were converted to NH₃ which then reacted with a <u>known excess of HCl</u>. This excess was later quantified via titration with NaOH.
First we calculate the <u>total amount of H⁺ moles from HCl</u>:
- 0.0388 M HCl * 10.00 mL = 0.388 mmol H⁺
Now we calculate the <u>excess moles of H⁺</u> (the moles that didn't react with NH₃ from the protein), from the <u>titration with NaOH</u>:
- HCl + NaOH → H₂O + Na⁺ + Cl⁻
- 0.0196 M * 3.83 mL = 0.075068 mmol OH⁻ = 0.0751 mmol H⁺
Now we substract the moles of H⁺ that reacted with NaOH, from the total number of moles, and the result is the <u>moles of H⁺ that reacted with NH₃ from the protein</u>:
- 0.388 mmol H⁺ - 0.0751 mmol H⁺ = 0.313 mmol H⁺ = 0.313 mmol NH₃
With the moles of NH₃ we know the moles of N, then we can <u>calculate the mass of N</u> present in the aliquot:
- 0.313 mmol NH₃ = 0.313 mmol N
- 0.313 mmol N * 14 mg/mmol = 4.382 mg N
From the exercise we're given the concentration of N in the protein, so now we <u>calculate the mass of protein</u>:
- 4.382 mg * 100/15.7 = 27.91 mg protein
Finally we <u>calculate the protein concentration in mg/m</u>L, <em>assuming your question is in 647 μL</em>, we first convert that value into mL:
- 647 μL *
0.647 mL
- 27.91 mg / 0.647 mL = 431.38 mg/mL
Answer:
The answer is Iron phosphide (Fe2P)
10% solution means=
=
= 100 mg/mL
If the dentist inject 0.3 mL, that is equal to 0.3× 100 mg.
If the dentist inject 0.3 mL, that is equal to 30 mg.
So, as anesthetic procaine hydrochloride is often used to deaden pain during dental surgery. the compound is packaged as a 10.% solution (by mass; d = 1.0 g/ml) in water. When our dentist
injects 0.30 ml of the solution, 30 mg of procaine hydrochloride (in milligrams) is injected.
Answer:
3, because H2 ×3 =6, and if you plug in a two in NH3 it would be equal