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3 years ago

Where on a bicycle might you find a pulley?

Chemistry

2 answers:

Akimi4 [234]3 years ago

8 0

I would say the chain rings

Lunna [17]3 years ago

3 0

I agree.
The chain rings...
I guess you could perhaps include pedals as well because they are attached to the gears and the help the chain move.
However pedals are mostly classified as lever.

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A certain first-order reaction a → b is 25% complete in 42 min at 25°c. What is the half-life of the reaction?.

kicyunya [14]

Half life of the reaction is :-101.9 min

a→b

25% reacted means 75% remains

t=42 min

Rate constant

k=(2.303/t)(log a/a-x)

k=(2.303/42)(log 100/100-25 )

k=(0.054) (log 100/75)

k=(0.054)(0.1249)

k=0.0068per min

half life

t1/2=(0.693/k)

=(0.693/0.0068)

=101.9 min

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2 years ago

At what point would a chemical bond form between two atoms.

PIT_PIT [208]

Answer:Chemical bonds form when the valence electrons of one atom interact with the valence electrons of another atom.J

Explanation: Byee stay safe: Wear your mask, drink water and stan bts

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2 years ago

A 50.0 mL solution of 0.141 M KOH is titrated with 0.282 M HCl . Calculate the pH of the solution after the addition of each of

Kobotan [32]

Answer:

pH =1 2.84

Explanation:

First we have to start with the reaction between HCl and KOH:

$HCl~+~KOH->~H_2O~+~KCl$

Now for example, we can use a volume of 10 mL of HCl. So, we can calculate the moles using the molarity equation:

$M=\frac{mol}{L}$

We know that $10mL=0.01L$ and we have the concentration of the HCl $0.282M$ , when we plug the values into the equation we got:

$0.282M=\frac{mol}{0.01L}$

$mol=0.282*0.01$

$mol=0.00282$

We can do the same for the KOH values ( $50mL=0.05L$ and $0.141M$ ).

$0.141M=\frac{mol}{0.05L}$

$mol=0.141*0.05$

$mol=0.00705$

So, we have so far 0.00282 mol of HCl and 0.00705 mol of KOH. If we check the reaction we have a molar ratio 1:1, therefore if we have 0.00282 mol of HCl we will need 0.00282 mol of KOH, so we will have an excess of KOH. This excess can be calculated if we substract the amount of moles:

$0.00705-0.00282=0.00423mol~of~KOH$

Now, if we want to calculate the pH value we will need a concentration, in this case KOH is in excess, so we have to calculate the concentration of KOH. For this, we already have the moles of KOH that remains left, now we need the total volume:

$Total~volume=50mL+10mL=60mL$

$60mL=0.06L$

Now we can calculate the concentration:

$M=\frac{0.00423mol}{0.06L}$

$M=0.0705$

Now, we can calculate the pOH (to calculate the pH), so:

$pOH=-Log(0.0705)$

$pOH=1.15$

Now we can calculate the pH value:

$14=~pH~+~pOH$

$pH=14-1.15=12.84$

8 0

3 years ago

Which of the following is the balanced equation for the

NNADVOKAT [17]

A.) is the answer =)

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3 years ago

Where is the ion charge located in the isotope symbol

Juliette [100K]

The ion charge located in the isotope symbol on the top right corner. The number part of an isotope's name is the Mass Number (P + N). A negativelycharged ion (anion) will have more Electrons than Protons. Cl 1- has one more electron than proton; 18 electrons, 17 protons. That's why its charge is 1-.

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3 years ago