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yKpoI14uk [10]
3 years ago
8

If a bag contains 12 quarters, 6 dimes, and 18 nickles, what is the part-to-whole ratio of nickles to all coins?

Mathematics
2 answers:
gladu [14]3 years ago
5 0
There are 18 nickels and 36 total coins
18:36 is your original proportion, but we can simplify.
Divide by 2
9:18
Divide by 9.
1:2 is your final answer.
A.) is correct.
Allisa [31]3 years ago
3 0

Answer:

I think A)1:2 is the correct answer

Step-by-step explanation:

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Solve the inequality 4-5<25
SVETLANKA909090 [29]

Answer:

4_5=_1 then -1 is <25 25_1 25<-1

8 0
2 years ago
The total cost, in dollars, to order x units of a certain product is modeled by C(x)=5x²+320 . According to the model, for what
lora16 [44]

Answer:

The minimum cost per unit is obtained for an order of 8 units.

Step-by-step explanation:

Since the total cost is modeled by;

C(x)=5x²+320

Then;

1 unit costs; C(x)=5(1)²+320 = 325

cost per unit 325/1 = 325

8 units costs; C(x)=5(8)²+320 = 640

cost per unit = 640/8 = 80

80 units costs; C(x)=5(80)²+320 = 32320

Cost per unit = 32320/80 = 404

The minimum cost per unit is obtained for an order of 8 units.

7 0
2 years ago
Write the next 3 numbers in the pattern. 3,2,5,4,7,
Kipish [7]
6,9,8 hope you have a great day :D
3 0
2 years ago
What is the GCF of 48m5n and 81m2n2?
Lady bird [3.3K]
To find the GCF of the two terms, continuous division must be done.
What can be used to divide both terms such that there is not a remainder?
Start small, let's take 2. It could be a GCF.
Move up higher, say 3. Yes, it can be a GCF.
To see if there might be a greater common factor, divide the constants by 3.
48/3 = 16
81/3 = 27
Upon inspection and contemplation, there is no more common factor between 16 and 27. So, 3 is the GCF.

Moving on, when it comes to variables. The variable with the least exponents is easily the GCF. For the variable m, the GCF is m2 and for n, the GCF is n.

Combining the three, we have the overall GCF = 3m2n
7 0
3 years ago
Read 2 more answers
The base of a triangle is 9cm correct to the nearest cm.
OLEGan [10]

Answer:

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3 0
2 years ago
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