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2 years ago

Simpify the expression. -2(y + 3) -7y

Mathematics

1 answer:

jenyasd209 [6]2 years ago

4 0

-2y-6-7y
-9y-6
I hope that this helps!

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Show down below how do you get the answer 359 x 12?

bija089 [108]

Answer:

4308

Step-by-step explanation:

start by splitting 12 into 10 and 2

do 359 x 10 + 359 x 2

359x10= 3590

359x2= 718

3590+718=4308

6 0

3 years ago

What is the answer to the question?

Anuta_ua [19.1K]

Answer:

Given : PQ = RQ

to find : angle B

PQ = RQ
Angle B = angle QRP ( angle opposite to equal side are equal). ...(1)
angle QRP + 140° = 180° ( linear pair)
angle QRP = 180° - 140°
angle QRP = 40°
from equation (1)
Angle B = angle QRP = 40°

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B%20-%2064%20%7D%20" id="TexFormula1" title=" \sqrt{ - 64 } " alt=" \sqrt{ - 64 }

Kipish [7]

What’s the other number?

3 0

3 years ago

Please help. Pythagorean theorem

zheka24 [161]

25 because the first square is a 3 by 3= 9 and the other one is 36 which is 6 by 6 and the last one is 4 by 4 so the last one is 5 by 5 or 25

6 0

3 years ago

ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th

Misha Larkins [42]

Answer:

a. $P(E_1/A)=0.0789$

b. $P(E_2/A)=0.395$ \

c. $P(E_3/A)=0.526$

Step-by-step explanation:

Let $E_1,E_2,E_3$ are the events that denotes the good drive, medium drive and poor risk driver.

$P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20$

Let A be the event that denotes an accident.

$P(A/E_1)=0.01$

$P(A/E_2=0.03$

$P(A/E_3)=0.10$

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem, $P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}$

We have to find $P(E_1/A)$

Using the Bayes theorem

$P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}$

Substitute the values then we get

$P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}$

$P(E_1/A)=0.0789$

b.We have to find the probability Mr.Brophy is a medium driver

$P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395$

c.We have to find the probability Mr.Brophy is a poor driver

$P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526$

7 0

3 years ago