Line QR contains (2, 8) and (3, 10) Line ST contains points (0, 6) and (-2, 2). Lines QR and ST are (4 points)

1 answer:

3 0

Slope formula:
m = y2 - y1 / x2 - x1

Line QR: (2,8) (3,10)
m = 10 - 8 / 3 - 2 = 2 / 1 = 2

Line ST: (0,6) (-2,2)
m = 2 - 6 / -2 - 0 = -4/-2 = 2

c. parallel because the slopes are the same

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Which expression represents the distance between the points (11, 4) and (5,8)?

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Answer:

$\displaystyle d = 2\sqrt{13}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (11, 4) → x₁ = 11, y₁ = 4

Point (5, 8) → x₂ = 5, y₂ = 8

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formula]: $\displaystyle d = \sqrt{(5-11)^2+(8-4)^2}$
[√Radical] (Parenthesis) Subtract: $\displaystyle d = \sqrt{(-6)^2+(4)^2}$
[√Radical] Evaluate exponents: $\displaystyle d = \sqrt{36+16}$
[√Radical] Add: $\displaystyle d = \sqrt{52}$
[√Radical] Simplify: $\displaystyle d = 2\sqrt{13}$