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3 years ago

Simplify the following expression using the distributive property and then combining like terms.

Mathematics

2 answers:

Ksivusya [100]3 years ago

7 0

B i believe
Work=
4x+2(2x-4)+6
4x+4x-8+6
8x-14

Hope I helped, sorry if it’s wrong

Nikolay [14]3 years ago

6 0

4x + 4x - 8 + 6

8x - 14

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V7x – 1 = 3<br> Please help this is algebra 2

kumpel [21]

Solving for X

7vx−1=3

7vx=3+1

7vx=4

vx=4/7

x=4/7/v

x=4/7v

Solving for Y

7vx−1=3

7vx=3+1

7vx=4

vx=4/7

v=4/7/x

v=4/7x

Hope this helps, HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)

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2 years ago

Evaluate the expression for c = -9. -c = _____

Tom [10]

Answer:

- c = 9

Step-by-step explanation:

given c = - 9 ← multiply both sides by - 1

c × - 1 = - 9 × - 1 ⇒ - c = 9

5 0

3 years ago

Which is a prime number? A. 39 B. 49 C. 81 D. 89

Alexus [3.1K]

D: 89 is the prime number.

5 0

3 years ago

Read 2 more answers

In the square below, the two semi-circles are congruent. Find the area of the shaded region. If necessary, round your answer to

Jobisdone [24]

Let's start with the area of the square
$area \: square = s \times s = 8 \times 8 = 64$
now let's subtract the are of the two half circles.
two half circles are the same as one circle, and we know that the diameter of the circle is 8 (same as the side of a square) so it's radius is 8/2= 4 inches

$area \: circle = \pi {r}^{2} = \pi \times {4}^{2} = 16\pi$
now we just subtract and our answer is

$64 - 16\pi = 64 - 16 \times (3.14) = 13.73$

3 0

3 years ago

I need help with this problem, if anyone could help ASAP, that would be much appreciated. In the figure below, mROP = 125° Find

VARVARA [1.3K]

Answer:

mRP = 125°

mQS = 125°

mPQR = 235°

mRPQ = 305°

Step-by-step explanation:

Given that

mROP = 125°

∠ROP is a central angle

Then:

measure of arc RP, mRP = mROP = 125°

Given that

∠QOS and ∠ROP are vertical angles

Then:

mQOS = mROP = 125°

measure of arc QS, mQS = mROP = 125°

Given that

∠QOR and ∠SOP are vertical angles

Then:

mQOR = mSOP

Given that

The addition of all central angles of a circle is 360°

Then:

mQOS + mROP + mQOR + mSOP = 360°

250° + 2mQOR = 360°

mQOR = (360°- 250°)/2

mQOR = mSOP = 55°

And (QOR and SOP are central angles):

measure of arc QR, mQR = mQOR = 55°

measure of arc SP, mSP = mSOP = 55°

Finally:

measure of arc PQR, mPQR = mQOR + mSOP + mQOS = 55° + 55° + 125° = 235°

measure of arc RPQ, mRPQ = mROP + mSOP + mQOS = 125° + 55° + 125° = 305°

6 0

3 years ago