Answer:
18.28 m
Step-by-step explanation:
Given the flower garden in the question :
The shape is composite and can be divided into 2 semicirles and rectangle
The perimeter of a semicircle is the Circumference of the semicircle = πr
Hence, 2 semicirles = 2πr
Radius of semicircle = 2/2 = 1
Perimeter = 2 * 3.14 * 1² = 2 * 3.14 * 1 = 6.28 m
The perimeter of rectangle; length and width are 6m and 2 m respectively :
Perimeter of rectangle = 2(l + w) = 2(4+2) = 2(6) = 12m
Tve perimeter of garden = 6.28 + 12 = 18.28 m
Answer:48
Step-by-step explanation:
2x3=6x4x2=48
Hello,
y=2^(-x)
y=2^(2x)+3
==>2^(2x)+3=1/2^x
==>2^(3x)+3*2^x-1=0 (1)
Let's assume u=2^x
(1)==>u^3+3*u-1=0
which as 3 roots
u=0.322185354626 or
u = -0.161092677313 + i1.754380959784 or
u = -0.161092677313 - i1.754380959784.
Let's take the real solution
0.322185354626=2^x
==>x=ln(0.322185354626) / ln(2)
x=-1,6340371790199...
an other way is
f(x)=2^(3x)+3*2^x-1
f(-2)=1/64+3/4-1=-15/64 <0
f(-1)=1/8+1-1=1/8>0
==> there is a solution betheen -2<x<-1
If 10% of songs represents 6 songs,
then 100% of songs represents (100 * 6) / 10 = 60 songs
The playlist has a total of 60 songs.
1. It's all about pattern matching, as a lot of math is.
Letter A corresponds to letter J, as both are first in the names of their respective triangles.
Letter B corresponds to letter K, as both are second in the triangle names. Likewise, letter C corresponds to letter L, as both are last.
Realizing this, it should not be too much of a stretch to see
∠B ⇒ ∠K ∠C ⇒ ∠L AC ⇒ JL BC ⇒ KL2. Same deal. Match the patterns. Here, you're counting rings in the angle marks.
1 ⇒ 1, so A ⇒ R
2 ⇒ 2, so B ⇒ Q
since the figures are reportedly similar, you can continue in the same order to finish.
ABCD ~ RQPS3. The marked triangles cannot be similar. There are a number of ways to figure this. Basically, you want the ratios of sides to be the same for any similar triangles.
Here, you can eliminate the marked ones because the short side is too short relative to the others. (The average of the other two sides is double the short side in the similar triangles.)
